The probability that a cookie is randomly picked and it does not contain chocolate or nuts will be 0.52
As per the question statement, a box of assorted cookies has 36% of them containing chocolate and 12% containing nuts, and of those, again 8% contain both chocolate and nuts, and we are assuming that the rest of the cookies neither contain chocolate, nor nuts.
Based on the conditions and our assumptions provided in the above mentioned statement, we are required to calculate the probability that a cookie is randomly picked and it does not contain chocolate or nuts.
Considering the total number of cookies in the box to be 100%, since 36% of them containing chocolate and 12% containing nuts and the rest of the cookies are assumed to contain neither chocolate, nor nuts,
The probability that a cookie is randomly picked and it does not contain chocolate or nuts will be [{100 - (36 + 12)}/100]
= [(100 - 48)/100]
= (52/100)
= 0.52
Probability: It is a branch of Mathematics, that deals with the numerical descriptions concerning the extent to which an event is likely to occur, or how likely it is for a proposition to be true, and is measured by the ratio of the favorable cases to the whole number of cases possible.
To learn more about Probability, Click on the link below.
brainly.com/question/20393396
#SPJ4