The Difference of 4 and k, divided by 16.

Data for parking lot counts for 30 days. Do a line plot,or talies

Liono4ka [1.6K]

U can do tallies.. Its like little lines..That add up to 30.

8 0

3 years ago

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10

zvonat [6]

The approximate difference in the ages of the two cars, which depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

$FV=P\left(1-\dfrac{r}{100}\right)^n$

Here, (P) is the price of the product, (r) is the rate of annual depreciation and (n) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is $n_1$ . Thus, by the above formula for the first car,

$0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}$

Take log both the sides as,

$\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85$

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is $n_2$ . Thus, by the above formula for the second car,

$0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}$

Take log both the sides as,

$\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14$

The difference in the ages of the two cars is,

$d=4.85-3.14\\d=1.71\rm years$

Thus, the approximate difference in the ages of the two cars, which depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0

2 years ago

X + 2y =6 X- y =3 Solution?

VikaD [51]

Since one equation has a negative y and the other has a positive y, I'm going to use those since they cancel each other out. Before that, the two y's need to be equal to each other.

x+2y=6
x-y=3

Multiply the bottom equation by two so then you have:

x+2y=6
2x-2y=6

The y's now cancel out:

x=6
2x=6

Add them together

3x=12

Divide

x=4.

To find y, plug x into either equation (*don't have to do both, but I will)

(4)+2y=6
(4)-y=3

Subtract four

2y=2
-y=-1

Divide each

2y/2 = 2/2
y=1

-y/-1 = -1/-1
y=1

The answer is:
x=4
y=1

I hope that helps!

4 0

3 years ago

Read 2 more answers

Post assessment

lions [1.4K]

1. D
2. E
3. B
4. Pentagon
5. C

3 0

3 years ago

The claim is that the proportion of drowning deaths of children attributable to beaches is more than 0.25, and the sample statis

Ainat [17]

Answer:

The test statistic Z = 3.125