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2 years ago

What is the scale factor of the dilation of triangle DEF 3/10 3/7 7/3 7

Mathematics

2 answers:

dsp732 years ago

4 0

Answer:

Step-by-step explanation:

Ed2020

Rzqust [24]2 years ago

3 0

A)3/10
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Drag the tiles to the correct boxes to complete the pairs.Not all tiles will be used match the equations representing parabolas

IceJOKER [234]

Answer:

$y=-8.08$ -------> $y+8=3(x+2)^{2}$

$y=14.25$ -------> $y-14=-(x-3)^{2}$

$y=-7.625$ -----> $y+7.5=2(x+2.5)^{2}$

$y=17.25$ -------> $y-17=-(x-3)^{2}$

$y=-7.25$ -------> $y+7=(x-4)^{2}$

$y=6.25$ -------> $y-6=-(x-1)^{2}$

Step-by-step explanation:

we know that

The standard form of a vertical parabola is equal to

$(x-h)^{2}=4p(y- k)$

where

(h,k) is the vertex

the focus is (h, k + p)

and

the directrix is y = k - p

Part 1) we have

$y+8=3(x+2)^{2}$

Convert to standard form

$(x+2)^{2}=(1/3)(y+8)$

The vertex is the point $(-2,-8)$

$h=-2,k=-8$

$4p=1/3$

$p=1/12$

the directrix is equal to

$y = k-p$ -----> $y=-8-(1/12)=-8.08$

Part 2) we have

$y-14=-(x-3)^{2}$

Convert to standard form

$(x-3)^{2}=-(y-14)$

The vertex is the point $(3,14)$

$h=3,k=14$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y = 14-(-1/4)=14.25$

Part 3) we have

$y+7.5=2(x+2.5)^{2}$

Convert to standard form

$(x+2.5)^{2}=(1/2)(y+7.5)$

The vertex is the point $(-2.5,-7.5)$

$h=-2.5,k=-7.5$

$4p=1/2$

$p=1/8$

the directrix is equal to

$y = k-p$ -----> $y=-7.5-(1/8)=-7.625$

Part 4) we have

$y-17=-(x-3)^{2}$

Convert to standard form

$(x-3)^{2}=-(y-17)$

The vertex is the point $(3,17)$

$h=3,k=17$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y = 17-(-1/4)=17.25$

Part 5) we have

$y+7=(x-4)^{2}$

Convert to standard form

$(x-4)^{2}=(y+7)$

The vertex is the point $(4,-7)$

$h=4,k=-7$

$4p=1$

$p=1/4$

the directrix is equal to

$y = k-p$ -----> $y=-7-(1/4)=-7.25$

Part 6) we have

$y-6=-(x-1)^{2}$

Convert to standard form

$(x-1)^{2}=-(y-6)$

The vertex is the point $(1,6)$

$h=1,k=6$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y=6-(-1/4)=6.25$

4 0

2 years ago

You are looking down at a map. A vector u with |u| = 6 points north and a vector v with |v| = 5 points northeast. The crossprodu

lina2011 [118]

Answer: Hi!

First, UxV = sin(a)*IUI*IVI

where a is the angle between U and V, in this case 45°.

First, the cross product of UxV points:

Here you can use the right hand method,

Put your hand flat, so the point of your fingers point in the same direction that the first vector, in this case U, so your fingers will point to the north.

Now roll your fingers in the direction of the second vector, so here you will roll your fingers in the northeast direction. Now you will see that your thumb is pointing down, so the cross product of UxV points down.

And the magnitude is 6*5*sin(45) = 21.213

6 0

2 years ago

Consider the following equation. 9x2 − y2 = 6 (a) Find y' by implicit differentiation. y' = (b) Solve the equation explicitly fo

qaws [65]

Answer:

Step-by-step explanation:

Given is an equation in x and y as

$9x^2 - y^2 = 6$

We use implicit method to differentiate the above equation

18x-2yy'=0

y' = 9x/y

b) to solve the equation explicitly for y and differentiate to get y' in terms of x. y' = ±

We separate the variables as

$yy' =9x\\\frac{y^2}{2} =\frac{9x^2}{2} +C\\y^2 =9x^2+2C$

Take square root

$y=\sqrt{9x^2+2C} \\y=-\sqrt{9x^2+2C}$

6 0

2 years ago

The space inside a circle is the ___ of the circle. circumference diameter area radius

Phantasy [73]

Area is the inside of the circle

6 0

2 years ago

Read 2 more answers

PLS PLS HELP, I DONT WANT TO FAIL!!

Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

Given quadratic functions:

$\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}$

To find the time, in seconds, that the balloons collided at the highest point, substitute one equation into the other equation and rearrange to equal zero:

$\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}$