Answer: option c
Step-by-step explanation:
Find the x-intercept and y-intercept of each line.
To find the x-intercept, substitute
into the equation and solve for "x".
To find the y-intercept, substitute
into the equation and solve for "y".
- For the first equation:
x-intercept

y-intercept

Graph a line that passes through the points (7.25, 0) and (0, 9.66)
- For the second equation:
x-intercept

y-intercept

Graph a line that passes through the points (0.5, 0) and (0, -0.33)
Observe the graph attached. You can see that point of intersection of the lines is (5,3); then this is the solution of the system. Therefore:

Answer:
(5 ⋅ X) + (5 ⋅ 8) =
Step-by-step explanation:
Lizzie has 18 dimes and 12 quarters
<em><u>Solution:</u></em>
Let "d" be the number of dimes
Let "q" be the number of quarters
We know that,
value of 1 dime = $ 0.10
value of 1 quarter = $ 0.25
Given that LIzzie has 30 coins
number of dimes + number of quarters = 30
d + q = 30 ---- eqn 1
Also given that the coins total $ 4.80
number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80

0.1d + 0.25q = 4.8 ------ eqn 2
Let us solve eqn 1 and eqn 2
From eqn 1,
d = 30 - q ---- eqn 3
Substitute eqn 3 in eqn 2
0.1(30 - q) + 0.25q = 4.8
3 - 0.1q + 0.25q = 4.8
0.15q = 1.8
<h3>q = 12</h3>
From eqn 3,
d = 30 - 12
<h3>d = 18</h3>
Thus she has 18 dimes and 12 quarters
63 dollars 3 hours
21 dollars 1 hour
Answer:

Step-by-step explanation:
You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.
You will find when you look on your trig identity sheet that

so we will make that replacement, getting everything in terms of sin:

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

We can factor out the sin(theta), since it's common in both terms:

Because of the Zero Product Property, either
or

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

The next equation needs to first be solved for sin(theta):
so
and

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:
