All categories

3 years ago

Question: 15-4+ (7 - 5)

Mathematics

2 answers:

erastovalidia [21]3 years ago

7 0

Answer:

Step-by-step explanation:

15 - 4 + ( 7 - 5)

remember the order of operations

simplify parenthesis first

15 - 4 + ( 7 -5 )

15 - 4 + ( 2 )

now solve in order ( from left to right)

15 - 4 + 2

11 +2

GREYUIT [131]3 years ago

3 0

Answer:

Step-by-step explanation:

15 - 4 + 7 - 5 = 13

Simply expand the brackets and subtract and add accordingly.

You might be interested in

3. You want to have $4000 in your savings account after 2 years. Find the amount you should deposit for each of the situations d

pychu [463]

Answer:

Part A)

About $3767.34.

Part B)

About $3692.47.

Step-by-step explanation:

Part A)

Recall that compound interest is given by the formula:
$\displaystyle A = P\left(1+\frac{r}{n}\right)^{nt}$

Where A is the final amount, P is the initial amount, r is the interest rate, n is the number of times compounded per year, and t is the number of years.

To obtain $4000 after two years, let A = 4000 and t = 2.

Because the account pays 3% interest compounded monthly, r = 0.03 and n = 12.

Substitute and solve for P:

$\displaystyle \begin{aligned} (4000) & = P\left(1+\frac{(0.03)}{(12)}\right)^{(12)(2)} \\ \\ P & = \frac{4000}{\left(1+\dfrac{(0.03)}{(12)}\right)^{(12)(2)}} \\ \\ & \approx \$3767.34\end{aligned}$

In concluion, about $3767.34 should be deposited.

Part B)

Recall the formula for continuous compound:

$\displaystyle A = Pe^{rt}$

Where e is Euler's number.

Hence, let A = 4000, r = 0.04 and t = 2. Substitute and solve for P:

$\displaystyle \begin{aligned}(4000) & = Pe^{(0.04)(2)} \\ \\ P & = \frac{4000}{e^{(0.02)(4)}} \\ \\ & \approx \$3692.47 \end{aligned}$

In conclusion, about $3692.47 should be deposited.

8 0

2 years ago

A stack of one hundred fifty cards is placed next to a ruler, and the height of the stack is measured to be 5/8 inches.

DaniilM [7]

Divide 5/8 by 150, to see how thick each is, that'll give you 150 even pieces that add up to 5/8

$\bf \cfrac{\frac{5}{8}}{150}\implies \cfrac{\frac{5}{8}}{\frac{150}{1}}\implies \cfrac{5}{8}\cdot \cfrac{1}{150}\implies \cfrac{1}{8\cdot 30}\implies \cfrac{1}{240}$

5 0

3 years ago

Math Mean Help Please!

klemol [59]

84.5 would be the answer if rounded to the nearest tenth

8 0

3 years ago

Read 2 more answers

A^3+a+a^2+1 2a^2+2ab+ab^2+b^3

Vikentia [17]

$\frac{a^3+a+a^2+1}{a^3+a^2+ab^2+b^2} \cdot \frac{2a^2+2ab+ab^2+b^3}{a^3+a+a^2b+b} =\frac{a(a^2+1)+1(a^2+1)}{a^2(a+1)+b^2(a+1)} \cdot \frac{2a(a+b)+b^2(a+b)}{a(a^2+1)+b(a^2+1)} =\\\\=\frac{(a^2+1)(a+1)}{(a+1)(a^2+b^2)} \cdot \frac{(a+b)(2a+b^2)}{(a^2+1)(a+b)} = \frac{2a+b^2}{a^2+b^2}$

6 0

3 years ago

A school baseball team earned $3416.90 from selling 5716 tickets to their game. If grandstand tickets sold for 65 cents each and

expeople1 [14]

If all were grandstand tickets, revenue would be 0.65*5716 = 3715.40. It was actually 298.50 less than that. Each bleacher ticket sold drops the revenue by .25, so there were 298.50/.25 = 1194 bleacher tickets sold.

3 0

3 years ago