The middle angles of a rhombus are 90 degrees which means the other two angles of the triangle must total 90 degrees.
(8x +7) + (3x + 6) = 90
11x + 13 = 90
11x = 77
x = 7
<h3>
Answer: x = 7</h3>
Work Shown:
Multiply 10.5 by 2/3 to get
10.5*2/3 = 21/3 = 7
Answer:
the volume of this can only be solve as pedmas or diver prop
Step-by-step explanation:
the two x and four x with 3x+3x+6
The smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
What is the intermediate value theorem?
Intermediate value theorem is theorem about all possible y-value in between two known y-value.
x-intercepts
-x^2 + x + 2 = 0
x^2 - x - 2 = 0
(x + 1)(x - 2) = 0
x = -1, x = 2
y intercepts
f(0) = -x^2 + x + 2
f(0) = -0^2 + 0 + 2
f(0) = 2
(Graph attached)
From the graph we know the smallest positive integer value that the intermediate value theorem guarantees a zero exists between 0 and a is 3
For proof, the zero exists when x = 2 and f(3) = -4 < 0 and f(0) = 2 > 0.
<em>Your question is not complete, but most probably your full questions was</em>
<em>Given the polynomial f(x)=− x 2 +x+2 , what is the smallest positive integer a such that the Intermediate Value Theorem guarantees a zero exists between 0 and a ?</em>
Thus, the smallest positive integer that the intermediate value theorem guarantees a zero exists between 0 and a is 3.
Learn more about intermediate value theorem here:
brainly.com/question/28048895
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