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Levart [38]
3 years ago
11

Which is the graph of y=1/2x? A,B,C, or D

Mathematics
1 answer:
poizon [28]3 years ago
4 0

y = 1/2x

has a y intercept of 0

goes up 1 and over 2 to point (2,1)

it has a positive slope  ( going up from left to right)



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SOLVE THIS QUESTION!! 10 POINTS! Check image below for more help!
ch4aika [34]

Answer:

I believe the answer is 48 degrees.

Step-by-step explanation:

4 0
3 years ago
omar is saving to buy a game hes saved 30 dollars which is six-fifths of total game cost. how much does it cost?
Rzqust [24]
The game costs 25 dollars. If 6/5 = 30 then 5/5 would be 25
3 0
3 years ago
Two lines that intersect at 90 degree angles
Molodets [167]
That would be a right angle 
3 0
3 years ago
A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
  • zyx.

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

5 0
2 years ago
(pls help quick and explain how you got the answers for brainliest)
scoray [572]

You only have to apply the theorem of Pythagoras here. Remember the square on the hypotenuse (the longest side) is equal to the sum of the squares on the other two sides :

1. AB is the hypotenuse, so, according to the theorem we can write :

AB² = AC² + CB²

c² = 5² + 4²

c²= 25 + 16

c² = 41

applying the square root of 41 we get :

c ≈ 6.40 rounded to the hundred

The next cases are exactly the same thing so there is no need for explanation :

2.

AB is the hypotenuse here because it is the biggest side clearl :

AB² = AC² + CB²

25² = 15² + b²

Thus

b² = 25² - 15²

we just subtracted 15² on each side of the equation

b² = 625 - 225

b² = 400

applying the square root of 400 we get

b = √400 = 20

So AC = 20

3. The longest side is clearly AB = 60

So

AB² = AC² + CB²

60² = 40² + a²

subtracting 40² on each side of the equation we get :

a² = 60² - 40²

I let you finish this using your calculator and doing exactly like the previous cases

4.

AB is the hypotenuse,

AB² = AC² + CB²

23² = b² + 14²

Subtracting 14² from each side of the equation we get

b² = 23² - 14²

5.

AB is the biggest side :

AB² = AC² + CB²

29² = 23² + a²

We subtract 23² on each sides of the equation :

a² = 29² - 23²

You can finish with your calculator

6.

AB² = AC² + BC²

78² = b² + 30²

subtraction...

b² = 78² - 30²

Good luck :)

7 0
2 years ago
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