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gavmur [86]
4 years ago
14

Evaluate x + sq root(yz) when x = 3, y = 2, and z = –8.

Mathematics
1 answer:
Alex_Xolod [135]4 years ago
7 0
Just remember  \sqrt{-1} = i

Sub in the numbers:
3 + \sqrt{-16} = 3+  \sqrt{16}\sqrt{-1} = 3 + 4i
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How many 2/3 are in 8/9​
Mila [183]

Answer:

3/4 or 0.75 decimal

Step-by-step explanation:

Simplify the following:

(2/3)/(8/9)

Hint: | Write (2/3)/(8/9) as a single fraction.

Multiply the numerator by the reciprocal of the denominator, (2/3)/(8/9) = 2/3×9/8:

(2×9)/(3×8)

Hint: | In (2×9)/(3×8), divide 9 in the numerator by 3 in the denominator.

9/3 = (3×3)/3 = 3:

(2×3)/8

Hint: | In (2×3)/8, divide 8 in the denominator by 2 in the numerator.

2/8 = 2/(2×4) = 1/4:

Answer: 3/4

6 0
3 years ago
Read 2 more answers
S t are positive integers
Sindrei [870]

Given:

The expanded form of (x+s)(x-t) is x^2+Kx-40.

Where, s, t, K are positive integers.

To find:

The smallest possible value of K.

Solution:

The expanded form of (x+s)(x-t) is x^2+Kx-40. It means,

(x+s)(x-t)=x^2+Kx-40

x^2-tx+sx-st=x^2+Kx-40

x^2+(s-t)x-st=x^2+Kx-40

On comping both sides, we get

K=s-t              ...(i)

K is a positive integer if s>t.

And

st=40

The factor pairs of 40 are (1,40), (2,20), (4,10), (5,8), (8,5), (10,4), (20,2) and (40,1).

Since s>t, therefore the possible values for (s,t) are (8,5), (10,4), (20,2) and (40,1).

Using (i), find the value of K for each factor pair.

K=8-5=3  

K=10-4=6      

K=20-2=18          

K=40-1=39          

Therefore, the smallest possible value of K is 3.

3 0
3 years ago
Write an equation for the translation of y = |x|. 10.5 units left
Serjik [45]
It would be A because you have add them to find the y number 
3 0
3 years ago
Read 2 more answers
Please solve need help!
lions [1.4K]

Answer:

ST 45

Step-by-step explanation:

9x=4x+25

5x=25

x= 5

plug back in 9(5)

4 0
3 years ago
I need help:
Lunna [17]

Answer:

8 green tshirts

Step-by-step explanation:

8 0
3 years ago
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