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Rudik [331]
3 years ago
7

Since f(x, y) = 1 + y2 and ∂f/∂y = 2y are continuous everywhere, the region R in Theorem 1.2.1 can be taken to be the entire xy-

plane. Use the family of solutions in part (a) to find an explicit solution of the first-order initial-value problem y' = 1 + y2, y(0) = 0. y = Even though x0 = 0 is in the interval (−2, 2), explain why the solution is not defined on this interval. Since tan(x) is discontinuous at x = ± , the solution is not defined on (−2, 2).
Mathematics
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

(3x, 6)

(3, 8)

Step-by-step explanation:

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