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Rudik [331]
3 years ago
7

Since f(x, y) = 1 + y2 and ∂f/∂y = 2y are continuous everywhere, the region R in Theorem 1.2.1 can be taken to be the entire xy-

plane. Use the family of solutions in part (a) to find an explicit solution of the first-order initial-value problem y' = 1 + y2, y(0) = 0. y = Even though x0 = 0 is in the interval (−2, 2), explain why the solution is not defined on this interval. Since tan(x) is discontinuous at x = ± , the solution is not defined on (−2, 2).
Mathematics
1 answer:
IceJOKER [234]3 years ago
7 0

Answer:

(3x, 6)

(3, 8)

Step-by-step explanation:

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Can someone help me with this
Ugo [173]

Answer:

~ 12.57

Step-by-step explanation:

6 0
3 years ago
Find the equation of a parabola with a focus at (0,-1) and a directrix at y = 4.
Anastasy [175]

Answer:

  y = -1/10x^2 +2.5

Step-by-step explanation:

The distance from focus to directrix is twice the distance from focus to vertex. The focus-directrix distance is the difference in y-values:

  -1 -4 = -5

So, the distance from focus to vertex is p = -5/2 = -2.5. This places the focus 2.5 units below the vertex. Then the vertex is at (h, k) = (0, -1) +(0, 2.5) = (0, 1.5).

The scale factor of the parabola is 1/(4p) = 1/(4(-2.5)) = -1/10. Then the equation of the parabola is ...

  y = (1/(4p))(x -h) +k

  y = -1/10x^2 +2.5

_____

You can check the graph by making sure the focus and directrix are the same distance from the parabola everywhere. Of course, if the vertex is halfway between focus and directrix, the distances are the same there. Another point that is usually easy to check is the point on the parabola that is even with the focus. It should be as far from the focus as it is from the directrix. In this parabola, the focus is 5 units from the directrix, and we see the points on the parabola at y=-1 are 5 units from the focus.

5 0
3 years ago
3
Lynna [10]

Answer:

C

Step-by-step explanation:

greatest spread for the middle 50% of data refers to the IQR, or interquartile range

A) IQR = 5

B) IQR = 5

C) IQR = 7

D) IQR = 6

6 0
3 years ago
Sweatshirt = $32 t-shirts = $14 ,
rodikova [14]
Cost of a sweatshirt = $32
Then
Cost of 14 sweatshirts = (32 * 14) dollars
                                     = 448 dollars
Cost of a t-shirt = $14
Cost of 32 t-shirts = (32 * 14) dollars
                               = 448 dollars
So it can seen from the deduction that the cost of 14 sweatshirts and 32 t-shirts comes out to be same and equal to $448. I hope the answer and the procedure of doing this problem is clear to you. It is important to look at all the details given in the question and then start solving the problem.
4 0
3 years ago
Read 2 more answers
40. In a statistics class of 30 students, there were 13 men and 17 women. Two of the men and three of the women received an A in
Harrizon [31]

Answer:

a) 56.67% probability that the student is a woman

b) 16.67% probability that the student received an A

c) 63.33% probability that the student is a woman or received an A.

d) 83.33% probability that the student did not receive an A.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

We have that:

30 students

13 men

17 women

2 men that got an A and 11 men that did not get an A.

3 women that got an A and 14 women that did not get an A.

a. Find the probability that the student is a woman.

30 students, of which 17 are women.

P = \frac{17}{30} = 0.5667

56.67% probability that the student is a woman

b. Find the probability that the student received an A.

30 students, of which 5 received an A

P = \frac{5}{30} = 0.1667

16.67% probability that the student received an A

c. Find the probability that the student is a woman or received an A.

30 students, of which 17 are women and 2 are men who received an A. So

P = \frac{19}{30} = 0.6333

63.33% probability that the student is a woman or received an A.

d. Find the probability that the student did not receive an A.

30 students, of which 25 did not receive an A.

P = \frac{25}{30} = 0.8333

83.33% probability that the student did not receive an A.

7 0
3 years ago
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