Since f(x, y) = 1 + y2 and ∂f/∂y = 2y are continuous everywhere, the region R in Theorem 1.2.1 can be taken to be the entire xy-
plane. Use the family of solutions in part (a) to find an explicit solution of the first-order initial-value problem y' = 1 + y2, y(0) = 0. y = Even though x0 = 0 is in the interval (−2, 2), explain why the solution is not defined on this interval. Since tan(x) is discontinuous at x = ± , the solution is not defined on (−2, 2).
It should show 2:45. You can use 12 hr increments to get you back to 10:45 and 12 goes into 100 nine times bringing it to 96. Because of that you have 4 more hours to add to 10:45 and that brings you to 2:45.
