Can anyone please explain this to me??

Scorpion4ik [409]

Answer:

9.85

Step-by-step explanation:

I hate these, LOL

We're going to draw a triangle on the graph paper to solve this. (in theory)

The top point is at 2 on the x axis, and the bottom is at 6. That's a difference of 4. Draw a line from the top dot over 4 spaces, so a line dropped from there could go straight to the bottom dot. We'll call this line/side of the triangle a, and a = 4.

Then we drop the line from there (6, 4) down to the second dot at (6, -5). That line is 9 places long. We'll call this line/side of the triangle b, and b = 9.

(This is so much easier to draw than type, I'll attach a picture).

Then we connect the two dots diagonally to form line/side c of our triangle. This is the length we don't know.

The pythagorean theorem says a^2 + b^2 = c^2

So a = 4, b = 9, c is unknown for our triangle

(4)(4) + (9)(9) = c^2

16 + 81 = 97

The square root of 97 = 9.8488, so if they have you round, I would say 9.85

Sorry if this just confused you more.

5 0

3 years ago

Is 2/5 equal to 0.25 equal

zhenek [66]

No because 2/5 equals 4/10, which is .4, not .25 :)

6 0

3 years ago

Read 2 more answers

What is the missing value? The Volume is 5120 m^3

Neko [114]

I think that the missing value is 16m.

I just multiplied two other numbers with 20 and 20 x 16 x 16 = 5120

I hope this was right.

7 0

3 years ago

A violin student records the number of hours she spends practicing during each of nine consecutive weeks: 6.2 5.0 4.3 7.4 5.8 7.

spin [16.1K]

Answer:

A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

Step-by-step explanation:

Assuming this complete question: A violin student records the number of hours she spends practicing during each of nine consecutive weeks:

6.2 5.0 4.3 7.4 5.8 7.2 8.4 1.2 6.3

For this case we need to sort the data first on increasing way and we got:

1.2, 4.3, 5.0, 5.8, 6.2, 6.3, 7.2, 7.4, 8.4

For this case we have 9 values the median would be on the 5 position:

$Median = 6.2$

The first quartile would be 5 since we analyze 1.2, 4.3, 5.0, 5.8, 6.2 and the middle point is 5.0

The third quartile would be 7.2 since we analyze 6.2, 6.3, 7.2, 7.4, 8.4 and the middle point is 7.2

Then the interquartile rnage would be:

$IQR = Q_3 -Q_1= 7.2-5=2.2$

And $1.5 IQR = 1.5*2.2=3.3$

The lower limit on this case would be:

$LL= Q_1 -1.5 IQR= 5-3.3=1.7$

And our value is 1.2 is lower than the lower limit 1.7

Considering the smallest data value (1.2) and using the 1.5 × IQR rule, we would:

A) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the first quartile.

Correct we satisfy that 1.2 <1.7 the lower limit

B) not classify the value 1.2 as an outlier, because it is not more than 1.5 × IQR below the first quartile.

False 1.2 is more than 1.5 IQR below the first quartile

C) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the median.

False, we analyze if is an outlier comparing with the Q1 or Q3 not with the median

D) classify the value 1.2 as an outlier, because it is more than 1.5 × IQR below the mean.

False we analyze if is an outlier comparing with the Q1 or Q3 not with the mean

5 0

3 years ago

A plane can fly 1440 miles in the same time as it takes a car to go 400 miles. If the car travels 130 mph

patriot [66]

Answer:

The speed will be "144 mph".

Step-by-step explanation:

Let the speed of the plane be "x mph".

then,

The car's speed be "x-130 mph".

According to the question,

⇒ $\frac{1440}{x} =\frac{400}{x-130}$

By applying cross-multiplication, we get

⇒ $1440(x-130)=400x$

⇒ $1440x-187200=400x$

⇒ $1440x-140x=187200$

⇒ $1300x=187200$

⇒ $x=\frac{187200}{1300}$

⇒ $=144 \ mph$

8 0

2 years ago