Answer:
The simplified system is the arbitrary solution of the original system of equations.
Y=9
X=6
Step-by-step explanation:
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Answer:
<u>600 meters</u>
Step-by-step explanation:
<u>Case 1 : Speed of 1 m/s</u>
- d = v * t
- d = 1 * t
- d = t [Equation 1]
<u>Case 2 : Speed of 1.5 m/s</u>
- d = v * t
- d = 1.5 * (t - 200)
- d = 1.5t - 300 [Equation 2]
As distance in both cases is the same, equate the values of d from both equations.
- t = 1.5t - 300
- 0.5t = 300
- t = 300 * 2
- <u>t = 600 s</u>
Now, put the value of t in <u>Equation 1</u> to find d.
Y-y1=m(x-x1)
y+5=14/3* (x+3)
y+5= (14/3)x+14
y=(14/3)x+9
(14/3)x+9-y=0 /*3
14x-3y+27=0
The general form of a solution of the differential equation is already provided for us:
where 
. We now want to find a solution 
such that 
and 
. Therefore, all we need to do is find the constants 
and 
that satisfy the initial conditions. For the first condition, we have:
For the second condition, we need to find the derivative 
first. In this case, we have:
Therefore:
This means that we must solve the following system of equations:
If we add the equations above, we get:
If we now substitute 
into either of the equations in the system, we get:
This means that the solution obeying the initial conditions is:
Indeed, we can see that:
which do correspond to the desired initial conditions.
Answer: x = 14
Step-by-step explanation:
-x+14 = 0
Subtract 14 from both sides of the equation :
-x = -14
Multiply both sides of the equation by (-1) : x = 14
