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3 years ago

(7m-35=5+2m) how do I solve for m???

Mathematics

2 answers:

Slav-nsk [51]3 years ago

4 0

First add 35 to both sides. Second subtract 2m from both sides. Lastly divide both sides by 5.

Elena L [17]3 years ago

3 0

Isolate m using inverse operations, get m by itself. (addition and subtraction, mult. and div.)

$7m-35=5+2m\ (subtract\ 2m) \\ 5m-35=5\ (add\ 35) \\ 5m = 40\ (divide\ by\ 40) \\ \boxed{m=8}$

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P( x) =x^3-6x^2-5x-14 What is the remainder R when the polynomial p(x) is divided by (x-7)

Igoryamba

Answer:

The remainder is zero

Step-by-step explanation:

To find the remainder we will use the long division

$\frac{x^{3}-6x^{2}-5x-14}{x-7}=x^{2}\frac{x^{2}-5x-14 }{x-7}$ ⇒(1)

$\frac{x^{2}-5x-14}{x-7}=x\frac{2x-14}{x-7}$ ⇒(2)

$\frac{2x-14}{x-7}=2$ ⇒(3)

From (1) , (2) and (3)

The quotient of the long division is $x^{2}+x+2$ and no remainder

So the remainder is zero

* If you want to check your answer Multiply the quotient by the divisor

$(x^{2}+x+2)(x-7)=x^{3}-6x^{2}-5x-14$

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3 years ago

What is the measure of angle x? Enter your answer in the box. m∠x= °

Llana [10]

The value of x is 83.
This is because all three angles of a triangle must sum up to 180 degrees. So 53+44=97 and 180-97=83.

3 0

3 years ago

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How do i solve this radical expression? It has to do with factoring i know that.

MAVERICK [17]

Firstly it's not a radical expression.

You can factorize the numerator x²+12x+36 = (x+6)²

Factorize the denominator 12x+72 = 12(x+6)

=(x+6)² / 12(x+6) , simplify. Answer = (x+6)/12

5 0

3 years ago

Kevin buys

algol [13]

Answer:

1:350 i think

Step-by-step explanation:

i could be wrong

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2 years ago

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Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal pla

svp [43]

Here is the correct computation of the question given.

Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal place. Listed below are the systolic blood pressures (in mm Hg) for a sample of men aged 20-29 and for a sample of men aged 60-69.

Men aged 20-29: 117 122 129 118 131 123

Men aged 60-69: 130 153 141 125 164 139

Group of answer choices

Men aged 20-29: 4.8%

Men aged 60-69: 10.6%

There is substantially more variation in blood pressures of the men aged 60-69.

Men aged 20-29: 4.4%

Men aged 60-69: 8.3%

There is substantially more variation in blood pressures of the men aged 60-69.

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

Men aged 20-29: 7.6%

Men aged 60-69: 4.7%

There is more variation in blood pressures of the men aged 20-29.

Answer:

(c)

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

Step-by-step explanation:

From the given question:

The coefficient of variation can be determined by the relation:

$coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100$

We will need to determine the coefficient of variation both men age 20 - 29 and men age 60 -69

To start with;

The coefficient of men age 20 -29

Let's first find the mean and standard deviation before we can do that ;

SO .

Mean = $\dfrac{\sum \limits^{n}_{i-1}x_i}{n}$

Mean = $\frac{117+122+129+118+131+123}{6}$

Mean = $\dfrac{740}{6}$

Mean = 123.33

Standard deviation $= \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }$

Standard deviation = $\sqrt{\dfrac{(117-123.33)^2+(122-123.33)^2+...+(123-123.33)^2}{(6-1)} }$

Standard deviation = $\sqrt{\dfrac{161.3334}{5}}$

Standard deviation = $\sqrt{32.2667}$

Standard deviation = 5.68

The $coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100$

$coefficient \ of \ variation = \dfrac{5.68}{123.33}*100$

Coefficient of variation = 4.6% for men age 20 -29

For men age 60-69 now;

Mean = $\dfrac{\sum \limits^{n}_{i-1}x_i}{n}$

Mean = $\frac{ 130 + 153 + 141 + 125 + 164 + 139}{6}$

Mean = $\dfrac{852}{6}$

Mean = 142

Standard deviation $= \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }$

Standard deviation = $\sqrt{\dfrac{(130-142)^2+(153-142)^2+...+(139-142)^2}{(6-1)} }$

Standard deviation = $\sqrt{\dfrac{1048}{5}}$

Standard deviation = $\sqrt{209.6}$

Standard deviation = 14.48

The $coefficient \ of \ variation = \dfrac{standard \ deviation}{mean}*100$

$coefficient \ of \ variation = \dfrac{14.48}{142}*100$

Coefficient of variation = 10.2% for men age 60 - 69

Thus; Option C is correct.

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

4 0

3 years ago