Answer:
The program in Java is as follows:
import java.util.*;
public class Main{
public static void main(String[] args) {
int n, num;
Scanner input = new Scanner(System.in);
System.out.print("Number of inputs: ");
n = input.nextInt();
LinkedList<Integer> myList = new LinkedList<Integer>();
for(int i = 0; i<n;i++){
System.out.print("Input Integer: ");
num = input.nextInt();
while (num > 0) {
myList.push( num % 10 );
num/=10;
}
while (!myList.isEmpty()) {
System.out.print(myList.pop()+" ");
}
System.out.println();
myList.clear();
}
}
}
Explanation:
This declares the number of inputs (n) and each input (num) as integer
int n, num;
Scanner input = new Scanner(System.in);
Prompt for number of inputs
System.out.print("Number of inputs: "); n = input.nextInt();
The program uses linkedlist to store individual digits. This declares the linkedlist
LinkedList<Integer> myList = new LinkedList<Integer>();
This iterates through n
for(int i = 0; i<n;i++){
Prompt for input
System.out.print("Input Integer: ");
This gets input for each iteration
num = input.nextInt();
This while loop is repeated until the digits are completely split
while (num > 0) {
This adds each digit to the linked list
myList.push( num % 10 );
This gets the other digits
num/=10;
}
The inner while loop ends here
This iterates through the linked list
while (!myList.isEmpty()) {
This pops out every element of thelist
System.out.print(myList.pop()+" ");
}
Print a new line
System.out.println();
This clears the stack
myList.clear();
}
