Suppose we have a 4096 byte byte-addressable memory that is 32-way high-order interleaved, what is the size of the memory addres
s module offset field?
a. 10
b. 7
c. 5
d. 4
1 answer:
Answer:
7
Explanation:
Given that :
Byte-addressable memory = 4096
Order = 32
Rwqritying such that they have the same base ;
4096 = 2^12
32 = 2^5
2^12 - 2^5
12 - 5 = 7
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