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Mkey [24]
3 years ago
7

Suppose we have a 4096 byte byte-addressable memory that is 32-way high-order interleaved, what is the size of the memory addres

s module offset field?
a. 10

b. 7

c. 5

d. 4
Computers and Technology
1 answer:
iogann1982 [59]3 years ago
4 0

Answer:

7

Explanation:

Given that :

Byte-addressable memory = 4096

Order = 32

Rwqritying such that they have the same base ;

4096 = 2^12

32 = 2^5

2^12 - 2^5

12 - 5 = 7

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