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Alborosie
3 years ago
6

What is the order of magnitude of the gravitational force between two 1.0 kilogram charges that are positioned 1.0 meter apart?

Physics
1 answer:
stiks02 [169]3 years ago
6 0

The answer is  -11

Enjoy!

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Waves with higher amplitude transfer ____energy.
natali 33 [55]

Answer:

- Waves with higher amplitude transfer HIGHER energy.

- Waves with higher frequency transfer HIGHER energy.

3 0
3 years ago
This is a Physics worksheet. please help.
natulia [17]

i think the answer is A

7 0
3 years ago
A woman lifts her 100-N child up one meter and carries her for a distance of 50m tl the childs bedroom . How muchwork does the w
BlackZzzverrR [31]
     The Definition of Work is given by:

T=F\Delta S
 
     Entering the unknowns, we have:

T=F\Delta S \\ T=100*50 \\ \boxed {T=5*10^3J}

If you notice any mistake in my english, please let me know, because i am not native.
6 0
4 years ago
A skier starts from rest and accelerates down a slope 2 at 23 m/s^2. How much time required for the skier to reach a speed of 9.
gayaneshka [121]

The skier's speed at time <em>t</em> is

<em>v</em> = (23 m/s²) <em>t</em>

To reach a speed of 9.3 m/s, the skier would need

9.3 m/s = (23 m/s²) <em>t</em>

<em>t</em> = (9.3 m/s) / (23 m/s²)

<em>t</em> ≈ 0.404 s

6 0
3 years ago
A 0.500-kg mass suspended from a spring oscillates with a period of 1.36 s. How much mass must be added to the object to change
lord [1]

The mass that must be added is 0.628 kg

Explanation:

The period of a mass-spring system is given by

T=2\pi \sqrt{\frac{m}{k}}

where

m is the mass

k is the spring constant

For the initial mass-spring system in the problem, we have

m = 0.500 kg

T = 1.36 s

Solving for k, we find the spring constant:

k=(\frac{2\pi}{T})^2 m = (\frac{2\pi}{1.36})^2 (0.500)=10.7 N/m

In the second part, we want the period of the same system to be

T = 2.04 s

Therefore, the mass on the spring in this case must be

m=(\frac{T}{2\pi})^2 k =(\frac{2.04}{2\pi})^2 (10.7)=1.128 kg

Therefore, the mass that must be added is

\Delta m = 1.128 - 0.500 = 0.628 kg

Learn more about period:

brainly.com/question/5438962

#LearnwithBrainly

5 0
4 years ago
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