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Darya [45]
3 years ago
9

He has 54 cds and every box has 9 cds.how many boxes are in 54 cds?

Physics
1 answer:
Gemiola [76]3 years ago
6 0

Solution:
54 / 9 = 6 boxes.
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Will mark brainliest!
MaRussiya [10]

Answer:

Explanation:

Fa - u*m*g = m*a

Fa = u*m*g + m*a

Fa - m*a = u*m*g

u = \frac{Fa - m*a}{m*g}

8 0
3 years ago
In the following figure, if AB ǁ CD, then find the measure of PCD and CPD.​
mina [271]

Answer:

CPD = 80

PCD = 44

Explanation:

Given

AB || CD

BAD = 56

CPA = 100

See attachment

Required

Determine PCD and CPD

First, we need to calculate CPD

Since DPA is a straight line and CPA = 100;

We have that:

CPA + CPD = 180 --- angle on a straight theorem

Substitute 100 for CPA

100 + CPD = 180

Subtract 100 from both sides

100-100 + CPD = 180-100

CPD = 80

Next, we calculate PCD

We have that:

DAB= ADC = 56  --alternate angle

In triangle PCD

PCD + CPD + PDC = 180 --- angles in a triangle

Where

PDC = ADC = 56

So, we have:

PCD +80 + 56 = 180

PCD +136 = 180

Subtract 136 from both sides

PCD = 180 - 136

PCD = 44

6 0
3 years ago
When all else remains the same, what effect would decreasing the focal length have on a convex lens?
aniked [119]
<h3>Answer;</h3>

<u>It would make the lens stronger. </u>

<h3>Explanation;</h3>
  • The focal length is the distance between the optical center or the center of the lens to the focal point of a convex or concave lens.
  • The power of the convex lens is lens ability to undertake refraction or bend light. It is given as the reciprocal of focal length.
  • Power of the lens = 1/ f; therefore the smaller the focal length the higher the power and the larger the focal length the lower the power.
  • Thus; decreasing the focal length of a convex lens makes the lens stronger.

4 0
3 years ago
Read 2 more answers
A 1000-kg whale swims horizontally to the right at a speed of 6.0 m/s. it suddenly collides directly with a stationary seal of m
Sphinxa [80]

M = mass of the whale = 1000 kg

m = mass of the seal = 200 kg

V = initial velocity of whale before collision with the seal = 6.0 m/s

v = initial velocity of the seal before collision with the whale = 0 m/s

V' = final velocity of two sea creatures after collision = ?

Using conservation of momentum

M V + m v = (M + m) V'

inserting the above values in the equation

(1000 kg) (6.0 m/s) + (200 kg) (0 m/s ) = (1000 kg + 200 kg) V'

6000 kgm/s + 0 kgm/s = (1200 kg) V'

V' = (6000 kgm/s ) /(1200 kg)

V' = 5 m/s

3 0
3 years ago
Read 2 more answers
If the velocity of gas molecules is doubled, then it’s kinetic energy will?( hint formula for kinetic energy is KE=.5 x mv2)
eduard

Answer:

D quadruple

Explanation:

E = \frac{1}{2}mv^2\\E'=\frac{1}{2}m(2v)^2=\frac{1}{2}m4 v^2 = 4(\frac{1}{2}mv^2)=4E

7 0
3 years ago
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