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Snezhnost [94]
4 years ago
9

Five metal samples, with equal masses, are heated to 200oC. Each solid is dropped into a beaker containing 200 ml 15oC water. Wh

ich metal will cool the fastest?
A) aluminum
B) copper
C) gold
D) platinum
Physics
2 answers:
Neporo4naja [7]4 years ago
6 0

Answer:

aluminum...

Explanation:

Ratling [72]4 years ago
5 0
<span>B) copper is the answer       shoot im late </span>
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PLEASE HELP ASAP
emmainna [20.7K]
Aluminum comes from several sources; it rarely occurs in pure form in nature, and is most frequently found embedded in other minerals, primarily bauxite. This would be most commonly found in the dirt.
4 0
3 years ago
Read 2 more answers
How far can a person run in 15 minutes if he or she runs at an average speed of 16 km/hr
Studentka2010 [4]
4 km/hr. There are four quarters in an hour, so just divide 16 by 4 and you get 4. It is directly proportional.
6 0
3 years ago
What was a pattern in nature that contributed to an understanding of atoms?
devlian [24]

the fact that chemicals have different colors

7 0
2 years ago
Suppose a 2662 kg giant seal is placed on a scale and produces a 20.0 cm compres- sion. If the seal and spring system are set in
Yuki888 [10]

Answer:

  0.8976 seconds

Explanation:

The period of oscillation for the simple harmonic motion can be found using the formula ...

  T = 2π√(d/g)

where d is the displacement of the spring due to the attached weight, and g is the acceleration due to gravity.

__

For d = 0.20 meters, the period is ...

  T = 2π√(0.20/9.8) ≈ 0.8976 . . . . seconds

_____

<em>Additional comment</em>

The formula for the oscillator period is usually seen as ...

  T = 2π√(m/k)

where m is the mass in the system and k is the spring constant. The value of the spring constant is calculated from ...

  k = mg/d

Using that in the formula, we find it simplifies to ...

  T=2\pi\sqrt{\dfrac{m}{k}}=2\pi\sqrt{\dfrac{m}{\left(\dfrac{mg}{d}\right)}}=2\pi\sqrt{\dfrac{d}{g}}

5 0
2 years ago
A speaker fixed to a moving platform moves toward a wall, emitting a steady sound with a frequency of 205 Hz. A person on the pl
Arlecino [84]

Answer:

Explanation:

The question relates to Doppler effect and beat.

The observer is moving towards the reflected sound so apparent frequency will be increased

f = f₀ x (V + v₁) / (V - v₂)

f is apparent frequency , f₀ is real frequency , V is velocity of sound , v₁ is velocity of observer and v₂ is velocity of source . Here

v₁ = v₂ = vp as both observer and source have same velocity

f = f₀ x (V + v₁) / (V - v₂)

205 +5 = 205 x (344 +vp)/ ( 344 - vp)

1.0234 = (344 +vp)/ ( 344 - vp)

= 352 - 1.0234vp = 340+vp

12 / 2.0234vp

vp = 6 m /s approx.

6 0
3 years ago
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