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4 years ago

If heat is transferred away from a gas, which could happen?

Physics

1 answer:

inessss [21]4 years ago

5 0

The answer would be B) The gas may become a liquid as it loses energy.

hope this helps you

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What is space mostly composed of?

miv72 [106K]

Nothing it nor breatheable you could die and it cold

8 0

3 years ago

A loop circuit has a resistance of R1 and a current of 1.8 A. The current is reduced to 1.6 A when an additional 3.8 Ω resistor

Allisa [31]

Answer:

Value of $R_1=30.4ohm$

Explanation:

We have given

In first case resistance is $R_1$ and current is 1.8 A

Let the potential difference is v

So $1.8=\frac{v}{R_1}$ ----eqn 1

In second case resistance is $R_1+3.8$ and current is 1.6 A and potential difference will be as it is a series connection

So $1.6=\frac{v}{R+3.8}$ ----eqn 2

From eqn 1 and eqn 2

$1.8R_1=1.6R_1+6.08$

$R_1=30.4ohm$

6 0

3 years ago

Read 2 more answers

Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.

Sladkaya [172]

Answer:

0.001 s

Explanation:

The force applied on an object is equal to the rate of change of momentum of the object:

$F=\frac{\Delta p}{\Delta t}$

where

F is the force applied

$\Delta p$ is the change in momentum

$\Delta t$ is the time interval

The change in momentum can be written as

$\Delta p=m(v-u)$

where

m is the mass

v is the final velocity

u is the initial velocity

So the original equation can be written as

$F=\frac{m(v-u)}{\Delta t}$

In this problem:

m = 5 kg is the mass of the fist

u = 9 m/s is the initial velocity

v = 0 is the final velocity

F = -45,000 N is the force applied (negative because its direction is opposite to the motion)

Therefore, we can re-arrange the equation to solve for the time:

$\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s$

4 0

3 years ago

Black_prince [1.1K]

What is happening to this sound is that it’s vibrating over and over.

4 0

3 years ago

A ball is projected at an immovable wall with a speed vi and bounces back the wall in such a manner that it only has 1/3 of its

sergey [27]

The fraction of the kinetic energy of the ball lost during the collision is $\frac{1}{3}$ .

The given parameters;

initial speed of the ball, = vi
final momentum of the ball, Pf = ¹/₃Pi

The initial and final momentum of the ball is calculated as;

$P_i = m_ivi$

$P_f = m_fv_f = \frac{1}{3} m_iv_i$

The initial and final kinetic energy of the ball is calculated as;

$K.E_i = \frac{1}{2} m_iv_i^2 = \frac{1}{2} P_iv_i\\\\K.E_f = \frac{1}{2} m_fv_f^2= \frac{1}{2} (\frac{1}{3} P_iv_i)= \frac{1}{6} P_iv_i$

The change in the kinetic energy is calculated as;

$\Delta K.E = K.E_f - K.E_i \\\\\Delta K.E = \frac{1}{6} P_iv_i - \frac{1}{2} P_iv_i = \frac{1}{3} P_iv_i$

Thus, the fraction of the kinetic energy of the ball lost during the collision is $\frac{1}{3}$ .

Learn more here:brainly.com/question/18566218

5 0

3 years ago