Answer: a) x = 5 or -1 b) x = √3+2
c) x = -1/2 or -3/2
Step-by-step explanation:
a) (x − 2)² = 9
First step is to take the square root of both sides to eliminate the square
√ (x − 2)² = √9
x-2 = +-3
x = +3+2
x = 5 and;
x = -3+2
x = -1
x = 5 or -1
b) 3(x-2)² = 9
First we divide both sides by 3 to get;
(x-2)² = 9/3
(x-2)² = 3
Second step is to take the square root of both sides to eliminate the square
√(x-2)² = √3
x-2 = √3
x = √3+2
c) 6 = 24(x+1)²
Dividing both sides by 24, we have
6/24 = (x+1)²
1/4 = (x+1)²
Taking the square root of both sides we have
√1/4 = √(x+1)²
= +-1/2 = x+1
x = +1/2-1 = -1/2 and;
x = -1/2-1 = -3/2
x = -1/2 or -3/2
A) $15 ÷ 40% =
15×.4= 6
15+6= 21
B) $38 × .25=9.5
38-9.5=28.50
28.50×.06=1.71
28.50+1.17=30.21
I think this is how you do it. would wait for other answers as well to double check.
Hello,
A: roots: -1,-3
a point (-2,1)
Vertex=((-2,1)
y=k*(x+1)(x+3) using roots
but k*(-2+1)(-2+3)=1==>k*(-1)*1=1==>k=-1
eq: y=-(x+1)(x+3)
==>y=-(x²+3x+x+3)
==>y=-x²-4x-3
y=k(x+2)²+1 if x=-1,y=0 ==>k*1+1=0==>k=-1
==>y=-(x+2)²+1
Answer :A--> R,K
B)
y=k(x+4)²-2 and k=-1/2
y=-1/2(x+4)²-2
y=-1/2x²-4x-10
answer B--> I,≈W if it is written -1/2*x² (square has been forgotten)
C:
y=2x²-16x+30
y=2(x-4)²-2
answer : C-->S,J
D:
y=-(x+3)(x+1)
y=-x²-4x-3
=-(x+2)²+1
answer D--> V,L
E:
Here there is a problem: or the graph is wrong, or 2 equations are missing!
y=1(x+1)(x-3) using roots
y=x²-2x-3 ≈ T si it were -2x and not +2x.
y=(x-1)²-4 ≈H is it were -1 in place of +1 [H:y=(x+1)²-4]
This is the isosceles right triangle, the diagonal of a square, the thing that so upset the Pythagoreans. The two sides and diagonal of a square are in ratio 
so we get
We could have also gotten this using Trig:
Or by recognizing u=v because remaining angle is 45 so this must be isosceles so
Answer: 90
Step-by-step explanation:
If you do the following:
100% of 60 = 60
50% of 60 = 30
60 + 30 = 90
