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Trava [24]
3 years ago
15

In ΔSTU, the measure of ∠U=90°, SU = 7, UT = 24, and TS = 25. What ratio represents the tangent of ∠T?

Mathematics
1 answer:
Vinvika [58]3 years ago
6 0

Answer:

Tan T = 7/24

Step-by-step explanation:

Firstly, please check attachment to have a picture of the triangle we are solving.

Now, we are concerned with calculating the ratio that represents the tangent of angle T.

Mathematically, the tangent of an angle is the ratio of the length of the opposite to the length of the adjacent.

In this question, our opposite is 7 while the adjacent is 24.

Thus Tan T = 7/24

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On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y =
rosijanka [135]

Answer:

Well ,lets see∉ if you add theose numbers togetherФ it maybe it he answer is 4=67 *64  ---4 67x54 5xe4t4 6x

7 0
3 years ago
What’s is the value of n? HELP ASAP PLEASE
earnstyle [38]

Answer:

The answer should be 69°

Step-by-step explanation:

Each line is being cut by a transversal, that means that the degree on the other side of it, added with the given degree will add up to 180°

1. On the right, you need to find the interior angle where 160° is outside so you subtract 180° from 160° to find the angle inside. That gives you 20°

2. On the top left you have 131° so 180°-131°=49°

Next you add the angles you have and then subtract it from 180 to get the interior angle with n° outside.

3. 20°+49°=69°

4. 180°-69°=111°

Then you do the same thing as the beginning which would be n°+111°=180°

5. n°+111°=180°, that means n=69°

Hopefully that clears it up for you :)

7 0
3 years ago
According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati
Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0
3 years ago
Can someone help me and show the work pls.
Ivan

(1 & 2/3) ft = (1 ft) + (2/3 ft)

(1 & 2/3) ft = 12 inches + 12*(2/3) inches

(1 & 2/3) ft = 12 inches + 8 inches

(1 & 2/3) ft = 20 inches

If the tree grows 5 inches per year, then it will take 4 years to get to 20 inches since 5*4 = 20. You can also divide to get 20/5 = 4.

So it takes 4 years for the tree to grow 1&2/3 feet tall.

8 0
3 years ago
Read 2 more answers
Please help me I don’t understand this
Tomtit [17]

Answer:64

Step-by-step explanation:

67

4 0
2 years ago
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