Answer:
<u><em></em></u>
- <u><em>Yes, it is reasonable to expect that more than one subject will experience headaches</em></u>
Explanation:
Notice that where it says "assume that 55 subjects are randomly selected ..." there is a typo. The correct statement is "assume that 5 subjects are randomly selected ..."
You are given the table with the probability distribution, assuming, correctly, the binomial distribution with n = 5 and p = 0.732.
- p = 0.732 is the probability of success (an individual experiences headaches).
- n = 5 is the number of trials (number of subjects in the sample).
The meaning of the table of the distribution probability is:
The probability that 0 subjects experience headaches is 0.0014; the probability that 1 subject experience headaches is 0.0189, and so on.
To answer whether it <em>is reasonable to expect that more than one subject will experience headaches</em>, you must find the probability that:
- X = 2 or X = 3 or X = 4 or X = 5
That is:
- P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5).
That is also the complement of P(X = 0) or P(X = 1)
From the table:
- P(X = 0) = 0.0014
- P(X = 1) = 0.0189
Hence:
- 1 - P(X = 0) - P(X = 1) = 1 - 0.0014 - 0.0189 = 0.9797
That is very close to 1; thus, it is highly likely that more than 1 subject will experience headaches.
In conclusion, <em>yes, it is reasonable to expect that more than one subject will experience headaches</em>
Answer:
13 ≥ x
Step-by-step explanation:
<u>Larry has at least 3 more than Pat</u>
<u>Simplified</u>
Answer:
In naming a ray, we always begin with the letter of the endpoint (where the ray starts) followed by another point on the ray in the direction it travels. Since the vertex of the angle is the endpoint of each ray and our vertex is , each of our rays must begin with . Only fails to do so.
Answer:
Just use long subtraction by expanding the decimal places of the whole number. This is done by adding a point, and enough zeros to it to match the number of decimal digits in the other number (digits after the decimal point).
12345678
i.e: 5 - 2.48374827, 2.48374827 has 8 decimal digits, so add 8 zeros after the point.
=
1 1 1 1 1 1 1
5.00000000
-
2.48374827
_______________
2.51625173
7 + 3 = <u>1</u>0, 7 + 2 + <u>1</u> = <u>1</u>0, 8 + 1 + <u>1</u>= <u>1</u>0, 5 + 4 + <u>1</u> = <u>1</u>0, 2 + 7 + <u>1</u> = <u>1</u>0, 3 + 6 + <u>1</u> = <u>1</u>0, 1 + 8 + <u>1</u> = <u>1</u>0, 5 + 4 + <u>1</u> = <u>1</u>0, 2 + 2 + <u>1</u> = <u>5</u><u> </u><u>:</u><u> </u>5.00000000
This is basically borrowing a group of 10s which are the same as 1s in the next decimal place up.
For each digit except the first to the right, let 10 subtract that number from it and minus 1 since the 1 is carried over.
