Triangles congruent by ASA have two pairs of congruent sides and an included congruent angle.
The graph indicates that sides TV, HG, and AB are congruent, and that sides TU, FG, and BC are congruent. It also indicates that angles U, F, and C are congruent, and that angles G and B are congruent. Notice that angle U of triangle TUV is not an included angle; this eliminates triangle TUV as it can't be congruent to another triangle by ASA with the information provided.
That leaves triangles FGH and ABC. Evidently, angles G and B are included angles, so these triangles are congruent by ASA.
Answer:
b. ΔHGF and ΔABC
Answer:
12 2/12
or 12 1/6 ( simplified fraction)
Step-by-step explanation:
first add the whole numbers together :7+5-4+3=12-1=11 ( same denominator 12)
1/12 +7/12 -5/12 +11/12 = 14/12 ( improper fraction)
= 1 2/12 mixed fraction
11 + 1 2/12=12 2/12 or 12 1/6 ( simplified fraction)
Answer:
d. Approximate the standard normal distribution with the Student's t distribution
(0.2199 ; 0.2327)
Step-by-step explanation:
Given that :
Sample size, n = 31
Sample mean, xbar = 0.2258
Sample standard deviation, s = 0.0188
Confidence interval (C. I) :
xbar ± margin of error
Margin of Error : Tcritical * s/sqrt(n)
Degree of freedom, df = n - 1 = 31 - 1 = 30
Tcritical value :
T0.05/2, 30 = 2.042
Margin of Error = 2.042 * 0.0188/sqrt(31)
Margin of Error = 0.0068949
C. I = 0.2258 ± 0.0068949
Lower boundary : (0.2258 - 0.006895) = 0.2189
Upper boundary : (0.2258 - 0.006895) = 0.2327
(0.2199 ; 0.2327)
Given.
Radius of the Half sphere is 3 inches.
From the figure;
Radius of half sphere= Radius of cylinder= Radius of cone=3inches
Height of cone= 4inches.
Height of cylinder=6inches.
Volume of cone=(πr²h)/3
=(π3²×4)/3
=(12π) inch³
volume of cylinder= πr²h=π3²6=54π inch³
Volume of half sphere= (4/3) π r³=π(4×3³)/3 (1/2)=π×4×9/2=18π inch³
Total area of Composite figure=(12π +54π +18π) inch³
=84π inch³
=(84)× 22/7inch³
=12×22 inch³
=264inch³
Hope it helps...
Regards;
Leukonov/Olegion.
Step-by-step explanation:
and are two fractions that are greater than 1 but less than 2 with a denominator of 3;
The denominator is the lower number in a quotient
Numerator is the upper number in a quotient
To solve this problem, we need to think creatively:
A fraction is made up of a numerator and denominator.
The denominator in this case must be 3
The numerator can be any number;
since the solution of our fraction must be greater than 1, this implies that the numerator must higher than the denominator.
if the denominator is higher, we get a solution less than 1.
since the solution must be less than 2, the value lies between 1 and 2.
The solution to the problem is and
learn more:
fraction brainly.com/question/1757979
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