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2 years ago

I will give 100 points and please get it right

Mathematics

1 answer:

Kobotan [32]2 years ago

8 0

Answer:

2 7/10

Step-by-step explanation:

3/4+3/5=

Common Denominator: 20

Multiples of 4: 4, 8, 12, 16, 20

Multiples of 5: 5, 10, 15, 20

3x5=15

4x5=20

15/20

3x4=12

5x4=20

12/20

15/20+12/20= 27/20 = 2 7/10

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Which of the following statements about rational numbers is not correct? А All whole numbers are also rational numbers. B All ra

iren2701 [21]

Step-by-step explanation:

1736-8166x71662=8177103 :D

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3 years ago

PLEASE HELP ASAP

Andrei [34K]

Answer: 35 the digits both together = 8

Reverse it and add 2.

53+2 =55

55- 35 = 20

The required answer is 35 :)

Step-by-step explanation:

7 0

2 years ago

Jerry multiplied 3.04 x 7.091 and got the product 2.155664. Is his answer reasonable? Why or why not?

Readme [11.4K]

First we multiply the numbers ignoring the decimal and then place the decimal in the position

3.04 *7.091 = 2155664

Now the first number has two digits after the decimal and the second number has three digits after the decimal.

Therefore in the final result we have to move the decimal (2+3) =5 place from the left,

So the answer would be 21.55664

So, the correct answer is 21.55664

Jerry calculated the answer correctly , but made an error in the placement of the decimal point. The answer is not reasonable because 2.155664 and 21.55664 mean two completely different answer far apart from each other

6 0

2 years ago

44cm is rounded to nearest whole cm. Write down the maximum possible length it could have been.

sesenic [268]

Answer:

44.49 repeated

Step-by-step explanation:

Sorry for the wait

8 0

2 years ago

A bag contains 6 green counters, 4 blue counters and 2 red counters. Two counters are drawn from the bag at random without repla

Svetach [21]

Answer:

24.24%

Step-by-step explanation:

In other words we need to find the probability of getting one blue counter and another non-blue counter in the two picks. Based on the stats provided, there are a total of 12 counters (6 + 4 + 2), out of which only 4 are blue. This means that the probability for the first counter chosen being blue is 4/12

Since we do not replace the counter, we now have a total of 11 counters. Since the second counter cannot be blue, then we have 8 possible choices. This means that the probability of the second counter not being blue is 8/11. Now we need to multiply these two probabilities together to calculate the probability of choosing only one blue counter and one non-blue counter in two picks.

$\frac{4}{12} * \frac{8}{11} = \frac{32}{132}$ or 0.2424 or 24.24%

8 0

2 years ago