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zavuch27 [327]
3 years ago
12

BIG POINTS!!!+BRAINLIEST ANSWER! BONUS!!!

Mathematics
1 answer:
IgorC [24]3 years ago
4 0

Answer:

Originally

The number of coins in the first box was 67\ coins

The number of coins in the second box was 83\ coins

Finally

The number of coins in the first box is 50\ coins

The number of coins in the second box is 100\ coins

Step-by-step explanation:

Let

x-----> number of coins in the first box originally

y-----> number of coins in the second box originally

we know that

x+y=150

x=150-y -----> equation A

(y+17)=2(x-17) -----> equation B

substitute equation A in equation B

y+17=2x-34

y+17=2(150-y)-34

y+17=300-2y-34

y+2y=300-34-17

3y=249

y=83\ coins

Find the value of x

x=150-83=67\ coins

therefore

Originally

The number of coins in the first box was 67\ coins

The number of coins in the second box was 83\ coins

Finally

The number of coins in the first box is (67-17)=50\ coins

The number of coins in the second box is (83+17)=100\ coins

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Answer please cuz I'm very confused
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5x + 3y = - 53

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where m is the slope and c the y-intercept

rearrange 3x - 5y = - 15 into this form to obtain m → (subtract 3x from both sides)

- 5y = - 3x - 15 → divide all terms by - 5 )

y = \frac{3}{5} x + 3 → in slope-intercept form with m = \frac{3}{5}

given a line with slope m then the slope m₁ of a line perpendicular to it is

m₁ = - \frac{1}{m} = - 1 ÷ \frac{3}{5} = - \frac{5}{3}

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to find c substitute ( - 7, - 6) into the partial equation

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4 years ago
What is 18=j+4 plz help
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Answer:

Hope this helps

Step-by-step explanation:

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Which set is closed under subtractionWhich answer choice shows that the set of irrational numbers is not closed under addition
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Answer:

(a) Set of rational numbers

(b) \pi + (-\pi) = 0

Step-by-step explanation:

Solving (a): Set that is closed under subtraction

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For a set of number to be closed under subtraction, the following condition must be true

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Where

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The above is only true for rational numbers.

e.g.

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Solving (b): Choice not close under addition[See attachment for options]

As stated in (a)

For a set of number to be closed under subtraction, the following condition must be true

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Where

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\pi is irrational while 0 is rational

<em>In other words, they belong to different set</em>

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