A bag contains 15 blue marbles, 5 red marbles, and 11 green marbles. How many blue marbles must be removed
from the 31 marbles in the bag so that the probability of randomly drawing a blue marble is 1/3?
Answer:
7 blue marbles
Step-by-step explanation:
15 blue
5 red
11 green
Total = 31
Number of Blue marbles that must be removed to obtain a probability of :
P(blue) = 1/3
Probability = required outcome / Total possible outcomes
Let number of blue marble to be removed = x
Number of Blue becomes : 15 - x
Total becomes : 31 - x
P(blue) = 1/3
1/3 = (15 - x) / (31 - x)
1/3 * (31 - x) = 15 - x
(31 - x) / 3 = 15 - x
31 - x = 45 - 3x
-x + 3x = 45 - 31
2x = 14
x = 14 / 2
x = 7
Answer: 8
Step-by-step explanation: It's just GCF. The greatest common factor (GCF) of 8 and 16 is 8 (8 and 16 are both divisible by 8 but not by anything greater) which brings us to our answer.
Assuming there are no ties
Answer:
980100
Step-by-step explanation:
Let's start with the boys(we could also start with girls, it doesn't matter).
We can "choose" one of 11 boys for the gold medal. That athlete can't win any more medals, so there are 10 boys left.
We can then "choose" one of the 10 boys remaining for the silver medal. That athlete can't win any more medals, so there are 9 boys left.
We can lastly "choose" one of the 9 boys remaining for the bronze medal.
That makes 11 possible choices for gold medal * 10 possible choices for silver medal * 9 possible choices for bronze medal = 990 possible choices(for boys).
We can do the exact same for the girls, leaving us with 990 possible choices for the girls.
We then multiply the possible choices together to get 990*990=980100 possible ways to hand out the six medals
Answer:20% is the answer
Step-by-step explanation:
The problem ask to find how many solution does the equation sin(x) = 0.01 have in the interval [0,2pi]. Base on my calculation and further computation about the problem, and also by using diagram and forming the circle, the answer would be 2 solution. I hope you are satisfied with my answer and feel free to ask for more
