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krek1111 [17]
3 years ago
5

Can some help me with this math problem

Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Answer:

This is true when the shape is a cube because all the faces are equivalent. This isn't true when it is a rectangular prism because some faces have areas larger than other faces.

Step-by-step explanation:

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Suppose a square ABCD has a side length of 1 unit. The arcs BD and AC are circular arcs with centers at A and D, respectively. F
Likurg_2 [28]

Answer:

1-\frac{\sqrt{3} }{4}-\frac{\pi}{6}

Step-by-step explanation:

The missing figure is shown in the attachment

The area of the shaded region = Area of Square - (Area of sector AOB + Area of equilateral  triangle BOC + Area of sector COD)

Area of Sector AOB=Area of Sector COD=\frac{30}{360}*\pi*1^2=\frac{\pi}{12}

Area of equilateral triangle =\frac{1}{2}*r*\frac{\sqrt{3} }{2}*r=  \frac{1}{2}*1*\frac{\sqrt{3} }{2}*=\frac{\sqrt{3} }{4}

Area of shade region =1^2-\frac{\sqrt{3} }{4}-\frac{\pi}{12}*2

1-\frac{\sqrt{3} }{4}-\frac{\pi}{6}

6 0
3 years ago
Easy 5+5+5+5+5+5+555<br><br> this is soo easy<br> answer this for brainiest<br> 2+2+2+22+2+2+22
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Answer:

585 and 54

Step-by-step explanation:

4 0
2 years ago
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ivanzaharov [21]
What kid of math is this?
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What is the area of the figure below? The figure shows a parallelogram. the left side equals 5 inches. The bottom side equals 12
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Answer:

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Step-by-step explanation:

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