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krek1111 [17]
3 years ago
5

Can some help me with this math problem

Mathematics
1 answer:
kvasek [131]3 years ago
7 0

Answer:

This is true when the shape is a cube because all the faces are equivalent. This isn't true when it is a rectangular prism because some faces have areas larger than other faces.

Step-by-step explanation:

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What is the value of w?<br><br> A. 7<br> B. 3.5<br> C. 7square root of three<br> D. 14
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Answer:

<h3>D. 14.</h3>

\sf{\cos(30)  =  \frac{7 \sqrt{3} }{w} } \\  \sf{ \frac{ \sqrt{3} }{2}  =  \frac{7 \sqrt{3} }{w} } \\  \sf{w =  \frac{7 \sqrt{3} \times 2 }{ \sqrt{3} }  = 14}

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3 years ago
Three airlines serve a small town in Ohio. Airline A has 48% of all scheduled flights, airline B has 26% and airline C has the r
kozerog [31]

Answer:

0.5969 = 59.69% probability that it was a flight of airline A

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Left on time.

Event B: From airline A.

Probability of a flight leaving on time:

81% of 48%(airline A).

61% of 26%(airline B)

40% of 26%(airline C). So

P(A) = 0.81*0.48 + 0.61*0.26 + 0.40*0.26 = 0.6514

Probability of leaving on time and being from airline A:

81% of 48%. So

P(A \cap B) = 0.81*0.48 = 0.3888

What is the probability that it was a flight of airline A?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3888}{0.6514} = 0.5969

0.5969 = 59.69% probability that it was a flight of airline A

6 0
3 years ago
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