Answer:
![x=14](https://tex.z-dn.net/?f=x%3D14)
Step-by-step explanation:
we know that
If two figures are congruent, then its corresponding sides and its corresponding angles are congruent
In this problem
△MON≅△PQR
so
corresponding sides
MO≅PQ
MN≅PR
ON≅QR
corresponding angles
∠M≅∠P
∠O≅∠Q
∠N≅∠R
therefore
MN=PR
substitute the given values
![32=3x-10](https://tex.z-dn.net/?f=32%3D3x-10)
solve for x
![3x=32+10](https://tex.z-dn.net/?f=3x%3D32%2B10)
![3x=42](https://tex.z-dn.net/?f=3x%3D42)
![x=14](https://tex.z-dn.net/?f=x%3D14)
Too blury,take a good pic
The answer is 40..........
Answer:
B
Step-by-step explanation:
- 2 | 2 2 - 2 4
↓ - 4 4 - 4
--------------------------
2 - 2 2 0 ← remainder
Since the remainder = 0 then (x + 2) is a factor
quotient = 2x² - 2x + 2
7 is the number increased by 5 = 12