WORD PROBLEMS

Explain how you would find 45 x 7/9 mentally.

Novosadov [1.4K]

You would do 45 divided by 9 which is 5. Then you do 5x7= 35 and that's your answer

3 0

3 years ago

Anna is in a cave 42 feet below the cave entrance. She descends 10 feet, then ascends 15 feet. Find her new position relative to

Mademuasel [1]

Answer:

Her new position is 37 feet below the cave entrance

Step-by-step explanation:

Let us solve the question

∵ The cave entrance is the zero position

∵ Anna is in 42 feet below the cave entrance

→ Below zero means negative

∴ Anna is in -42 feet

∵ She descends 10 feet

→ Descend means negative

∴ She is in -42 + -10 = -52 feet

∵ She ascends 15 feet

→ Ascend means positive

∴ She is in -52 + 15 = -37 feet

→ -37 means she is in below the cave entrance by 37 feet

∴ Her new position is 37 feet below the cave entrance

8 0

3 years ago

A farmer wants to spray 3 gallons of pesticide equally on 10 farm plots. how many gallons of pesticide should he use for each pl

photoshop1234 [79]

3 gallons on 10 things

Here, we have less things to be distributed than the number of things you distribute to.

Thus: 3/10 gallons.

7 0

3 years ago

1. The position of a particle moving along a coordinate axis is given by: s(t) = t^2 - 5t + 1. a) Find the speed of the particle

zimovet [89]

Answer: $\left | 2t-5\right |,\ 2,\ 2t-5$

Step-by-step explanation:

Given

Position of the particle moving along the coordinate axis is given by

$s(t)=t^2-5t+1$

Speed of the particle is given by

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=\left | 2t-5\right |$

Acceleration of the particle is

$\Rightarrow a=\dfrac{dv}{dt}\\\\\Rightarrow a=2$

velocity can be negative, but speed cannot

$\Rightarrow v=\dfrac{ds}{dt}\\\\\Rightarrow v=\dfrac{d(t^2-5t+1)}{dt}\\\\\Rightarrow v=2t-5$

3 0

3 years ago

Find the domain and range of<br><br> f(x)= (2x+6) / ((x^2)-x-12)

creativ13 [48]

Answer:

Step-by-step explanation:

If you want to determine the domain and range of this analytically, you first need to factor the numerator and denominator to see if there is a common factor that can be reduced away. If there is, this affects the domain. The domain are the values in the denominator that the function covers as far as the x-values go. If we factor both the numerator and denominator, we get this:

$f(x)=\frac{2(x+3)}{(x-4)(x+3)}$

Since there is a common factor in the numerator and the denominator, (x + 3), we can reduce those away. That type of discontinuity is called a removeable discontinuity and creates a hole in the graph at that value of x. The other factor, (x - 4), does not cancel out. This is called a vertical asymptote and affects the domain of the function. Since the denominator of a rational function (or any fraction, for that matter!) can't EVER equal 0, we see that the denominator of this function goes to 0 where x = 4. That means that the function has to split at that x-value. It comes in from the left, from negative infinity and goes down to negative infinity at x = 4. Then the graph picks up again to the right of x = 4 and comes from positive infinity and goes to positive infinity. The domain is:

(-∞, 4) U (4, ∞)

The range is (-∞, ∞)

If you're having trouble following the wording, refer to the graph of the function on your calculator and it should become apparent.

8 0

3 years ago