Answer:
Ques 11: 123.08 meters.
Ques 12: 269.4 meters.
Ques 13: 211.27 meters.
Step-by-step explanation:
Ques 11: We have that the angle of elevation from the ship to the top of the lighthouse is 18° and the height of the lighthouse is 40 m.
It is required to find the distance of the ship from the shore, say 'x' m.
As, we have,
⇒
⇒
⇒
⇒ x = 123.08 m.
Thus, the distance of the ship from the shore is 123.08 meters.
Ques 12: We have, length of the kite is 300 m and the angle made by the string is 64°.
It is required to find the height of the kite, say 'x' m.
As, we have,
⇒
⇒
⇒
⇒ x = 269.4 m.
Hence, the height of the kite is 269.4 meters.
Ques 13: We have, the wreckage is found at the angle of 12° and the diver is lowered down by 45 meters.
It is required to find the distance covered by the diver to reach the wreckage, say 'x' m.
As, we have,
⇒
⇒
⇒
⇒ x = 211.27 m.
Thus, the distance covered by the diver to reach the wreckage is 211.27 meters.
Basically to solve this question, simply find 2 numbers that will multiply to give you 162, in this case it would be for instance, 27 and 6. Knowing that 27 is nothing but 9 • 3, and 6 is nothing but 3 • 2, you can then rewrite cube root 162 p^8 as cube root ( 9 • 3 • 3 • 2) p^8 this can be simplified further to ( 3 • 3 • 3 • 3 • 2 • p^8), take out 3 number 3's out as in cube root unlike square root you are taking 3 numbers that are the same out, do the same for the variable, so the maximum number of p's we can take out would be 6 p's and thus have 2 p's outside the radical. ( 3 p's for every 1 p outside).
The end result would be 3 • p • p cube root 3 • 2 • p^2.
3p^2 cube root 6p^2.
Answer:
-45.
Step-by-step explanation:
I am assuming you mean
√25 - 2(3 +4(-2))^2
= 5 - 2(3-8)^2
= 5 - 2 * (-5)^2
= 5 - 2*25
= -45.
You should choose 25% of $950 as that gives the higher amount of money.
15% of $1,500 = $225
25% of $950 = $237.5
Answer:
(500,0) , (300,0), (200,200) and (300,200)
Step-by-step explanation:
The region of the graph we are concerned with is that small portion which is shaded.
We need the coordinates that bounds this portion of the graph.
These coordinates are four in number and they are as identified by noticing the four points that surround the portion then making tracings from these points to the x and y axes respectively.
We proceed as follows;
The four points we are looking at in no particular order are;
(500,0) , (300,0), (200,200) and (300,200)
The points having coordinates that have y = 0 are those that are domiciled on the x-axis
We have two of these points which are on the x-axis.