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3 years ago

One period of y = 4sin(x) is graphed below.What is the domain of y = 4sin(x)?

Mathematics

2 answers:

Marta_Voda [28]3 years ago

8 0

Answer

The answer is (-infinity, infinity) or option choice B on plato

Step-by-step explanation:

Alinara [238K]3 years ago

5 0

The domain of this sine function is the entire set of real numbers. Since there is no real value of x for which sin(x) becomes undefined, then the entire set of reals is the domain.

(On the other hand, the range would be from -4 <= y <= 4, since the sine function can only have a value ranging from -1 to 1, and multiplying 4 expands that from -4 to 4.)

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For what values of x is XP 36-5x true?

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2 years ago

Which is the graph of f (x) = 4 (1/2) Superscript x?

miss Akunina [59]

Answer:

Option (2) is correct graph.

Step-by-step explanation:

Given:

The function to graph is given as:

$f(x)=4(\frac{1}{2})^x$

Now, the above function is an exponential function of the form $f(x)=ka^x$

Where, 'k' and 'a' are constants.

The range of an exponential function is always greater than 0.

The domain is all real numbers.

Now, for graphing it, we need to find some points on it and its end behaviour.

Now, for x = 0, the function value is given as:

$f(0)=4(\frac{1}{2})^0=4$

So, (0, 4) is a point on the graph.

Now, for x = 1, the function value is given as:

$f(1)=4(\frac{1}{2})^1=4\times\frac{1}{2}=2$

So, (1, 2) is another point on the graph.

Now, for x = 2, the function value is given as:

$f(2)=4(\frac{1}{2})^2=4\times\frac{1}{4}=1$

So, (2, 1) is another point on the graph.

Now, as 'x' tends to ∞, the function value tends to:

$f(x\to\infty)=4\cdot\frac{1}{2}^{\infty}=\frac{4}{\infty}=0$

So, as

$x\to\infty,f(x)\to0\\\\x\to-\infty,f(x)\to\infty$

Now, from among all the options, only option (2) fulfills all the conditions given above.

So, option (2) is correct graph.

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3 years ago

Mr Hughes is competing in the Mr. Legs campaign to raise money for the coral shores high school scholarship fund. On the first d

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