Plug in 0 for x
0 - 6y = 30
y = -5
Y intercept: (0,-5)
Plug in 0 for y
5x = 30
X = 6
X intercept: (6,0)
We have that
x²<span> + 7x + c
</span><span>Group
terms that contain the same variable
</span>(x² + 7x )+ c
<span>Complete
the square. Remember to balance the equation
</span>(x² + 7x+3.5² )+ c-3.5²
Rewrite as perfect squares
(x+3.5)²+ c-3.5²
so
c-3.5² must be zero
c-3.5²=0------- c=3.5²------> c=12.25
the answer isthe value of c must be 12.25
Answer:
113
Step-by-step explanation:
Let the number of adult tickets sold =a
Let the number of student tickets sold =s
A total of 259 tickets were sold, therefore:
a+s=259
Adult tickets were sold for $24 each and student tickets were sold for $16 each.
Total Revenue = $5,312
Therefore:
24a+16s=5,312
We solve the two derived equations simultaneously.
From the first equation
a=259-s
Substitute a=259-s into 24a+16s=5,312
24(259-s)+16s=5,312
6216-24s+16s=5,312
-8s=5,312-6216
-8s=-904
Divide both sides by -8
s=113
Therefore, 113 student tickets were sold.
It would be $13.52 for 11 cans of soup
B. Angle B= Angle E
As this would only prove the AAA Similarity theorem, but not any Congruence Rule
