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larisa86 [58]
3 years ago
10

Please help ! I don’t understand:((

Mathematics
1 answer:
zysi [14]3 years ago
5 0

Answer:

B

Step-by-step explanation:

sorry if im wrong but i used desmos next time its graphing use desmos

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Solve the inequality for x. Show each step of the solution.10x > 2(8x – 3) – 18
Luden [163]

Answer: x<4

Given the inequality:

10x>2(8x-3)-18

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First, distribute the bracket on the right side of the inequality.

\begin{gathered} 10x>2(8x)-2(3)-18 \\ 10x>16x-6-18 \\ 10x>16x-24 \end{gathered}

Next, subtract 10x from both sides of the inequality.

\begin{gathered} 10x-10x>16x-10x-24 \\ 0>6x-24 \end{gathered}

Add 24 to both sides of the inequality.

\begin{gathered} 0+24>6x-24+24 \\ 24>6x \end{gathered}

Divide both sides of the inequality by 6.

\begin{gathered} \frac{24}{6}>\frac{6x}{6} \\ 4>x \\ \implies x

The solution to the inequality is x<4.

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1 year ago
To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

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Step-by-step explanation:

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Libby's dog stands
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Step-by-step explanation:

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