Answer: C. The size of a business is ordinal-scaled because it has values that can be used as an order or rank of a categorical variable.
Step-by-step explanation: Ordinal variables are simply categorical in nature just like nominal variables, however, the difference exists in the fact that ordinal labels posses an ordered rank or level unlike nominal variables. Though the extent or width of the difference between these labels cannot be ascertained. In the scenario above, size of businesses are labeled qualitatively with labels such as : small, medium and large. This labels depicts and follow a certain order with small being the least, then medium, then large. Telling us large businesses are superior in size to small and medium and medium is superior to large. Though the extent of the difference cannot be accurately ascertained.
The <em>correct answers</em> are:
It would take 5 months and she would save $250.
Explanation:
Let m be the number of months.
For the first way of saving, $200 up front and $10 each month, the expression would be
200+10m.
For the second way of saving, $100 up front and $30 each month, the expression would be
100+30m.
Setting them equal gives us the equation
200+10m = 100+30m
Subtract 10m from each side:
200+10m-10m = 100+30m-10m
200 = 100+20m
Subtract 100 from each side:
200-100 = 100+20m-100
100 = 20m
Divide both sides by 20:
100/20 = 20m/20
5 = m
It would take 5 months.
$200 up front and $10 each month for 5 months:
200+10m
200+10(5)
200+50
250
She would save $250.
Answer:
about 4312
Step-by-step explanation:
You want the total cost for n CDs to be 3.50n.
The manufacturer will charge you 9700+1.25n, so you want these to be equal:
3.50n = 9700 +1.25n
2.25n = 9700 . . . . . . . . subtract 1.25n
n = 9700/2.25 ≈ 4311.111...
Producing 4312 CDs will make the cost per CD slightly less than $3.50.
____
Producing 4311 CDs will make the cost per CD be about $3.500058. Producing 4312 CDs will bring it down to $3.499536.
Answer:
(D) 
(E)
has a range of all real numbers.
Step-by-step explanation:
Given the function: 

When y=f(x)=0

Therefore, 
Also,
has a range of all real numbers.
Therefore, Options D and E are correct.