Answer:
55,30
Step-by-step explanation:
just did it
Step-by-step explanation:
![\sqrt{(x + 6) ^{2} } = \sqrt{18} \\ x + 6 = + - \sqrt{18} \\ x + 6 = + - \sqrt[3]{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28x%20%2B%206%29%20%5E%7B2%7D%20%7D%20%20%3D%20%20%5Csqrt%7B18%7D%20%5C%5C%20x%20%2B%206%20%3D%20%20%2B%20%20-%20%20%5Csqrt%7B18%7D%20%20%5C%5C%20x%20%2B%206%20%3D%20%20%2B%20%20-%20%20%5Csqrt%5B3%5D%7B2%7D%20)
x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Step-by-step explanation:
We need to solve the equation
and find values of x.
Solving:
Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)
Multiply the entire equation with x(x-1)

Now, factoring the term:

The values of x are x=1 and x=2
Checking for extraneous roots:
Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.
If we put x=1 in the equation,
the denominator becomes zero i.e
which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.
If we put x=2 in the equation,


So, x=2 is only solution while x=1 is extraneous solution
Option C is correct.
Keywords: Solving Equations and checking extraneous solution
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7/8 x = 21
7x = 21×8
7x = 168
x = 24
When lines are perpendicular it’s called parallel, it’s when the lines never touch