4500÷.15= 30,000
30,000+4500=$34,500 salary
        
             
        
        
        
Answer:
im try ing to think
Step-by-step explanation:
 
        
             
        
        
        
Answer:
First it says that you have to multiply the number x times 2, this will give you 2x as a result. Next you have to build your equation which is 2x=10, when you have an equation like this, you divide the result with the number before x (x=10÷2) your result will be x=5. Now you have to square the result (which is x) to get y, when squaring a number you have to multiply it by itself (depending of how many times it's asking to do so when there's a small number at the upper right corner of your number, that's how many times you multiply it) so if you have to square 5, it should be 5×5 which gives you the result of y being 25.
 
        
             
        
        
        
Answer:  The numbers are:  " 21 " and " 105 " .
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Explanation:
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Let "x" be the "one positive number:
Let "y" be the "[an]othyer number".
x = 1/5 (y)
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Given that the difference of the two number is "84" ;  and that "x" is (1/5) of  "y" ;  we determine that "x" is smaller than "y".
So, y − x = 84 .
Add "x" to each side of this equation; to solve for "y" in terms of "x" ;
y − x + x = 84 + x  ;
 y = 84 + x ;
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So, we have:  
 x = (1/5) y ;
and:  y = 84 + x  ;
Substitute "(1/5)y" for "x" ;  in  "y = 84 + x " ;  to solve for "y" ;
 y = 84 + [ (1/5)y ] 
Subtract  " [ (1/5)y ] " from EACH SIDE of the equation ;
y − [ (1/5)y ] = 84 + [ (1/5)y ] −  [ (1/5)y ]  ;
to get:
  [ (4/5)y ] = 84 ; 
       ↔    (4y) / 5 = 84  ;
      
        →  4y = 5 * 84  ;
      Divide EACH SIDE of the equation by "4" ; 
to isolate "y" on one side of the equation; and to solve for "y" ;
           4y / 4 = (5 * 84) / 4 ;
                 y =  5 * (84/4) = 5 * 21 = 105 .
   y = 105 .
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Now, plug "105" for "y" into:
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Either:
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 x = (1/5) y ;
OR:
  y = 84 + x  ;
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to solve for "x" ; 
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Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
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Start with:
x = (1/5)y 
    →  (1/5)*(105) = 105 / 5 = 21 ;  x = 21 ;  
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So, x = 21;  y = 105 .
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Now, let us see if this values hold true in the other equation:
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y = 84 + x ;
105 = ? 84 + 21 ?
 
105 = ? 105 ? Yes!
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The numbers are:  " 21 " and  "105 " .
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