Answer:
The triangles are not similar
Step-by-step explanation:
we know that
If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent
<em>Triangle X.Y.Z</em>
---> angle X and angle Y are complementary angles
<em>Triangle H.G.J</em>
---> angle H and angle J are complementary angles
so
X.Y.Z is a
triangle
H.G.J is a
triangle
The measure of its corresponding angles are not congruent
therefore
The triangles are not similar
Slope = (8+2)/(1 - 3) = 10/-2 = -5
answer
<span> −5 </span>
Answer:
197.2 million
Step-by-step explanation:
The appropriate exponential equation for the population is ...
p(t) = 172.0e^(0.019t)
Then we can compute for t=7.2:
p(7.2) = 172.0e^(0.019·7.2) ≈ 172.0·1.146599 ≈ 197.2
7.2 minutes from now, the population will be about 197.2 million.
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For continuous growth (or continuous compounding), the exponential formula is ...
f(t) = (value at t=0)×e^(rt)
where r is the growth rate in one unit of time, and t is the number of time periods.
Answer:
Angle DCA = Angle CAB. (Alternate Interior Angle)
Angle DCA = 68°
Angles(DCA + ACB + BCE) = 180°. (Linear Pair)
Angle ACB + 68° + 33° = 180°
Angle ACB = 79°
Therefore,
Angle ABC = 33°. (Alternate Interior Angle)
I've attached the complete question.
Answer:
Only participant 1 is not cheating while the rest are cheating.
Because only participant 1 has a z-score that falls within the 95% confidence interval.
Step-by-step explanation:
We are given;
Mean; μ = 3.3
Standard deviation; s = 1
Participant 1: X = 4
Participant 2: X = 6
Participant 3: X = 7
Participant 4: X = 0
Z - score for participant 1:
z = (x - μ)/s
z = (4 - 3.3)/1
z = 0.7
Z-score for participant 2;
z = (6 - 3.3)/1
z = 2.7
Z-score for participant 3;
z = (7 - 3.3)/1
z = 3.7
Z-score for participant 4;
z = (0 - 3.3)/1
z = -3.3
Now from tables, the z-score value for confidence interval of 95% is between -1.96 and 1.96
Now, from all the participants z-score only participant 1 has a z-score that falls within the 95% confidence interval.
Thus, only participant 1 is not cheating while the rest are cheating.
