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erica [24]
3 years ago
8

Which models show 40%? Check all that apply. A model with 4 shaded sections and 6 unshaded sections. A model with 40 shaded sect

ions and 60 unshaded sections. A model with 2 shaded sections and 8 unshaded sections.
Mathematics
2 answers:
Amanda [17]3 years ago
8 0

Answer:

A model with 4 shaded sections and 6 unshaded sections.

A model with 40 shaded sections and 60 unshaded sections.

Step-by-step explanation:

Required:

Which models shows 40%

(a) 4 shaded and 6 unshaded

First, we calculate the total sections

Total = 4 + 6

Total = 10

The percentage of the shaded section is:

Shaded = \frac{4}{10} * 100\%

Shaded = 0.4 * 100\%

Shaded = 40\%

(b) 40 shaded and 60 unshaded

First, we calculate the total sections

Total = 40 + 60

Total = 100

The percentage of the shaded section is:

Shaded = \frac{40}{100} * 100\%

Shaded = 0.4 * 100\%

Shaded = 40\%

(c) 2 shaded and 8 unshaded

First, we calculate the total sections

Total = 2 + 8

Total = 10

The percentage of the shaded section is:

Shaded = \frac{2}{10} * 100\%

Shaded = 0.2 * 100\%

Shaded = 20\%

<em>Hence, (a) and (b) shows 40%</em>

jok3333 [9.3K]3 years ago
6 0

Answer:

A model with 8 shaded sections and 2 unshaded sections.

What are the equivalent forms of the number shown in the model?

Word:

✔ eight-tenths

Fraction:

✔ 8/10 = 4/5

Decimal:

✔ 0.8

Step-by-step explanation:

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Di the products 40x 500 and 4x 600 have the same number of zeros? Explain
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As a marketing manager, you are tasked with selecting a website to place your advertisement. The following sampled data shows th
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Answer:

Kindly check explanation

Step-by-step explanation:

Given the data :

Website 1 : 10357, 10537, 10767, 10561, 10544, 10581, 10602, 10665, 10335, 10419, 10737, 10410, 10485, 10601, 10458, 10472, 10435, 10375, 10436, 10510, 10345, 10559, 10520, 10425, 10351, 10465, 10491, 10671, 10366, 10440, 10618, 10606, 10406, 10538, 10449, 10462

Mean, xbar = ΣX/ n ; n = sample size = 36

Xbar = 377999 / 36 = 10499.9722

Standard deviation, s = √[(x - xbar)² / (n-1]

Using calculator :

Standard deviation (Website 1 :), s = 110.239865

Website 2 : 11067, 11029, 10888, 10789, 10914, 10663, 10787, 11140, 11042, 11074, 10868, 10853, 10900, 11088, 10991, 10928, 10959, 11126, 11033, 11114, 11150, 11155, 11027, 10900, 11015, 11123, 10953, 11181, 10855, 10731, 10971, 10770, 11070, 11122, 11018, 10903

Mean, xbar = ΣX/ n ; n = sample size = 36

Xbar = 395197 / 36 = 10977.6944

Standard deviation, s = √[(x - xbar)² / (n-1]

Using calculator :

Standard deviation (Website 2), s = 132.617995

2.)

Yes, the viewership between the two websites are different with the second website has a higher mean viewership with a mean of 10977.6944.

3.)

The probability of 12000 views per month on each website :

Probability = Mean viewership per month / required viewership

Website 1 :

P(12000) = 10499.9722 / 12000 = 0.8749

Website 2 :

P(12000) = 10977.6944 / 12000 = 0.9148

4.)

More consistent website :

We use the standard deviation value, the higher the standard deviation, the higher the variability :

Website 1 should be more consistent has it has a Lower standard deviation score, hence, should show lower variability than website 2.

5.)

Website suitable for advertisement should be one with higher viewership per month in other to reach a larger audience. Hence, website 2 should be recommended for advertisement.

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