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3 years ago

Find value of each of the following 11+(-33)-(-7)

Mathematics

1 answer:

Dominik [7]3 years ago

5 0

Answer:

= 11-33+7

= 11+7-33

= 18-33

= -15

Step-by-step explanation:

if we multiple + by - then it becomes -

if we multiple - by - then it becomes +

by this way I have done

I hope this will help u .

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When both pipes are working together, how long does it take them to fill the tank?

AleksAgata [21]

Well, since 1 tank takes 60 minutes (hour) and the other takes 40 minutes , add those to get 100 minutes . Divide 6000 by 100 to see how long it takes to fill the tank

Answer :60 minutes or an hour

Hope this helps!

3 0

3 years ago

Carlene is selling T-shirts for a fundraiser. The T-shirts cost $20.50 each. To date, she has raised $700. Her goal is to raise

valina [46]

She needs to sell around 397 more shirts.

Divide 700 by 20.5. This will give you the amount of shirts she has already raised with is 36 (more accurately 36 6/41). Next divide 8900 by 20.5. This is the amount of shirts she needs to sell in total, which is 434. Subtract these two values.

4 0

3 years ago

Prove that sin3a-cos3a/sina+cosa=2sin2a-1

Sloan [31]

Answer:

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

Step-by-step explanation:

we are given

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

we can simplify left side and make it equal to right side

we can use trig identity

$sin(3a)=3sin(a)-4sin^3(a)$

$cos(3a)=4cos^3(a)-3cos(a)$

now, we can plug values

$\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}$

now, we can simplify

$\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}$

$\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}$

$\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}$

now, we can factor it

$\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}$

$\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can use trig identity

$sin^2(a)+cos^2(a)=1$

$\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}$

we can cancel terms

$=3-4(1-sin(a)cos(a))$

now, we can simplify it further

$=3-4+4sin(a)cos(a))$

$=-1+4sin(a)cos(a))$

$=4sin(a)cos(a)-1$

$=2\times 2sin(a)cos(a)-1$

now, we can use trig identity

$2sin(a)cos(a)=sin(2a)$

we can replace it

$=2sin(2a)-1$

so,

$\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1$

7 0

3 years ago

Read 2 more answers

QUESTION 1

I am Lyosha [343]

QUESTION 1
A survey of 85 randomly selected homeowners finds that they spend a mean of $67 per month on home maintenance with a standard
deviation of $14. Construct and interpret a 99% confidence interval for the mean amount of money spent per month on home
maintenance by all homeowners.
What is ?
If necessary, round your answer to three decimal places
QUESTION 2
0
A survey of 85 randomly selected homeowners finds that they spend a mean of S67 per month on home maintenance with a standard
deviation of $14. Construct and interpret a 99% confidence interval for the mean amount of money spent per month on home
maintenance by all homeowners.
What is the t-multiplier?
if necessary, round your answer to three decimal places.
Chick Save and Submit to save and submit. Click Save All Answers to save all answers.

3 0

3 years ago

Help please!!!!!!!!!!!!

Nady [450]

Answer:

Step-by-step explanation:

a. 1 & 2

b. 3 & 5

c. 2/15

d. 2/5 x 5/3

e. 10/15= 2/3

8 0

3 years ago