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3 years ago

8

10. Explain where to place the beam

1 answer:

cluponka [151]3 years ago

8 0

What type of beam are you talking about please explain. Thank you

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Free points everyone<br><br><img src="https://tex.z-dn.net/?f=10%20%2B%2062%20%5Cdiv%202" id="TexFormula1" title="10 + 62 \div 2

Brut [27]

41 is the right answer

8 0

3 years ago

Read 2 more answers

A right triangle has legs of 5 ft and 6 ft. What is the length of the hypotenuse? _____ ft. A. 7.8 B. 3.3 C. 11.0 D. 1.0

Delicious77 [7]

Answer:

<h2>7.8</h2>

Option A is the correct option.

Step-by-step explanation:

Base (b) = 5 ft

Perpendicular (P) = 6 ft

Hypotenuse (h) = ?

Now,

Using Pythagoras theorem,

${h}^{2} = {p}^{2} + {b}^{2}$

${h}^{2} = {(6)}^{2} + {(5)}^{2}$

${h}^{2} = 36 + 25$

${h}^{2} = 61$

$h = \sqrt{61}$

$h = 7.8 \: ft$

Hope this helps...

Good luck on your assignment

8 0

3 years ago

Find the solutions to the following linear-quadratic systems algebraically. Select the ordered pair that is one of the correct s

Ghella [55]

Answer:

(-2, 6)

Step-by-step explanation:

we have

$y=x^{2} +3x+8$ ----> equation A

$y=2x+10$ ----> equation B

equate equation A and equation B

$x^{2} +3x+8=2x+10$

$x^{2} +3x+8-2x-10=0$

$x^{2} +x-2=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^{2} +x-2=0$

so

$a=1\\b=1\\c=-2$

substitute in the formula

$x=\frac{-1\pm\sqrt{1^{2}-4(1)(-2)}} {2(1)}$

$x=\frac{-1\pm\sqrt{9}} {2}$

$x=\frac{-1\pm3} {2}$

$x=\frac{-1+3} {2}=1$

$x=\frac{-1-3} {2}=-2$

Find the values of y

For x=1

$y=2(1)+10=12$

For x=-2

$y=2(-2)+10=6$

therefore

The solutions are (1,12) and (-2,6)

3 0

3 years ago

a laptop computer is purchased for $4500. Each year, its value is 80% of its value the year before. After how many years will th

motikmotik

Answer:

So after 7 year price of the laptop will be less than $1000

Step-by-step explanation:

We have given price of the laptop is $4500

Its price is 80% of if its value in every next year

So depreciation rate = 100 - 80 =20%

For depreciation we know that

$V=P(1-r)^n$

Here V is final value and P is present value

So $1000=4500(1-0.2)^n$

$0.2222=(0.8)^n$

Taking log both side

$log0.222=nlog0.8$

n = 6.74

So after 6.74 year the price of the laptop will be less than $1000

7 0

3 years ago

How am I supposed to solve this question? (Letter e)

FinnZ [79.3K]

$\bf f(x)=x^2-3~\hspace{5em}\stackrel{x=3c}{f(3c)=(3c)^2-3} \\\\\\ f(3c)=(3^2c^2)-3\implies f(3c)=9c^2-3$

8 0

3 years ago