3 years ago

16th term in the geometric sequence 1024, -512, 256, ....

Mathematics

1 answer:

tresset_1 [31]3 years ago

5 0

Answer:-1/32

Step-by-step explanation:

First term=a=1024

Common ratio=r=-512/1024

r=-1/2

Using them formula

Tn=a x r^(n-1)

T16=1024 x (-1/2)^(16-1)

T16=1024 x (-1/2)^15

T16=1024 x -1/32768

T16=-1024/32768

T16=-1/32

You might be interested in

Multiply. (2x2 + 4x - 3)(x2 - 2x + 5)

BigorU [14]

For a moment, let $y=x^2-2x+5$ . Then by the distributive property,

$(2x^2+4x-3)p=2x^2p+4xp-3p$

Again by the distributive property,

$2x^2p=2x^2(x^2-2x+5)=2x^4-4x^3+10x^2$

$4xp=4x(x^2-2x+5)=4x^3-8x^2+20x$

$-3p=-3(x^2-2x+5)=-3x^2+6x-15$

Taking everything together, we get

$(2x^2+4x-3)(x^2-2x+5)=(2x^4-4x^3+10x^2)+(4x^3-8x^2+20x)+(-3x^2+6x-15)$
$(2x^2+4x-3)(x^2-2x+5)=2x^4-x^2+26x-15$