Let A be some subset of a universal set U. The "complement of A" is the set of elements in U that do not belong to A.
For example, if U is the set of all integers {..., -2, -1, 0, 1, 2, ...} and A is the set of all positive integers {1, 2, 3, ...}, then the complement of A is the set {..., -2, -1, 0}.
Notice that the union of A and its complement make up the universal set U.
In this case,
U = {1, 2, 3, 6, 10, 13, 14, 16, 17}
The set {3, 10, 16} is a subset of U, since all three of its elements belong to U.
Then the complement of this set is all the elements of U that aren't in this set:
{1, 2, 6, 13, 14, 17}
The greatest common multiple of 3 and 4 will be :
Answer:
(1, - 2 )
Step-by-step explanation:
Given the 2 equations
3x + y = 1 → (1)
5x + y = 3 → (2)
Subtracting (1) from (2) term by term eliminates the term in y, that is
(5x - 3x) + (y - y) = (3 - 1) and simplifying
2x = 2 ( divide both sides by 2 )
x = 1
Substitute x = 1 in either of the 2 equations for corresponding value of y
Using (1), then
3 + y = 1 ( subtract 3 from both sides )
y = - 2
Solution is (1, - 2 )
Answer: i've heard about it but i'm not too much into it
Your correct answer is option B
