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ikadub [295]
3 years ago
6

Which ones are they tell me all that apply?

Mathematics
1 answer:
Lelechka [254]3 years ago
5 0

On the first on it is the first answer and the last one.

second: the second and the third one.

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Determine the numerical length of JK.​
Zarrin [17]

Answer:

30

So the two sectors add to the full length:

JK + IJ = IK

x+6 + 9 = 2x

Rearrange:

x=15

So the numerical length:

2x

2*15

30

5 0
3 years ago
Read 2 more answers
Terrance is 3.5 years older than Stephanie. Stephanie is 22.5 years old.
LuckyWell [14K]

Answer:

Terrance is 25.5

Step-by-step explanation:

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3 years ago
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Nick goes to the store and buys 22 notebooks for $1.50 each. Then he buys 8 pens for $0.55 each. How much money did he spend in
rosijanka [135]

Answer:

$33 for the notebooks and $4.40 for the pens

Step-by-step explanation:

if u would multiply 33 by 1.50 you would get $33

if u would multiply 8 by 0.55 you would get $4.40

8 0
3 years ago
Exploring the graph of y equals cosine Theta​
irga5000 [103]

Answer:  see below

<u>Step-by-step explanation:</u>

The coordinates on the Unit Circle are (cos, sin). Since we are focused on cosine, we only need to focus on the left side of the coordinate. The cosine value (left side) will be the y-value of the function y = cos x

Use the quadrangles (angles on the axes) to represent the x-values of the function y = cos x.

Quadrangles are: 0°, 90°, 180°, 270°, 360°  <em>(360° = 0°)</em>

Together, the coordinates will be as follow:

\boxed{\begin{array}{c||c|c||c}\underline{(cos,sin)}&\underline{x=angle}&\underline{y=cosx}&\underline{\quad (x,y)\quad}\\(1,0)&0^o&1&(0^o,1)\\(0,1)&90^o&0&(90^o,0)\\(-1,0)&180^o&-1&(180^o,-1)\\(0,-1)&270^o&0&(270^o,0)\\(1,0)&360^o&1&(360^o,1)\end{array}}

8 0
3 years ago
Line I is a perpendicular bisector
kolezko [41]

Line I is a perpendicular bisector because it bisects another line at right angles via the point of intersection or midpoint. See the Perpendicular Bisector Theorem below.

<h3>What is the perpendicular bisector theorem?</h3>

According to the theorem of perpendicular bisector, any locus on the perpendicular bisector is equidistant from the terminal points of the line segment on which it is created.

Thus, Line I is a perpendicular bisector because it bisects another line at right angles via the point of intersection or midpoint. See the attached image.

Learn more about perpendicular bisectors at:
brainly.com/question/11006922
#SPJ1

4 0
1 year ago
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