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gregori [183]
4 years ago
7

HELPPPPPP ASAPPPPPPPP

Mathematics
1 answer:
Alisiya [41]4 years ago
5 0

Answer:

f(x)= 2x-5

f(-1) = 2(-1) -5

= -2 -5

= -7

g(x)= |-3x -1|

g(3)= |-3(3)-1|

=|-9 -1|

= |-10|

= 10

F(-1)- g(3)= -7-10 = -17

You might be interested in
How to construct a triangle with side lengths 10 cm and 14 cm and an angle between them of 60 degrees.
Yuliya22 [10]

Answer:

We draw line AB which is perpendicular to the 14 cm side

Since Angle C is 60 degrees that makes angle CAB = 30 degrees

Triangle CAB is a 30 60 90 triangle so line CB is half the hypotenuse or 5 cm

Line BD equals 9 cm

Line AB^2 = 10^2 - 5^2 = 75

Line AD^2 = AB^2 + BD^2

Line AD^2 = 75 + 81

Line AD^2 = 156

Line AD = 12.4899959968

Line AB = Sqr root (75) = 8.6602540378

Angle D = arc sine  (8.6602540378 / 12.4899959968)

Angle D = 43.898 degrees

Angle A = 180 - 60 - 43.898 = 76.102 degrees

*****************************************************************

Actually this could have been done a little easier by using the Law of Cosines and then the Law of Sines, but I just thought I'd show another way to solve this.

Step-by-step explanation:

4 0
3 years ago
danny completed 85% on his field goal attempts last season.if he attempted 60 field goals,how many did he make
Alexeev081 [22]
He scored 51
explanation:
60 x 0.85 = 51
8 0
3 years ago
I don't remember what it is that I'm doing, as I did the lessons before spring break. Help?
blsea [12.9K]
Extraneous solutions, is answers that we get because of squaring both sides of the radical equation, but in reality, they are not going to be the solutions of  the given equation.
(√(4x+41))²=(x+5)²
4x+41=x²+10x+25
x²+6x-16=0
(x-2)(x+8)=0
x1=2 , x2=-8,
And now we must to check them by substitution into initial equation

√(4x+41)=x+5
1)   x=2,   √(4*2+41)=2+5, √49=7, 7=7 true
2) x=-8,     √(4*(-8)+41)=-8+5,   √9 =-3    false,
so an extraneous solution x=-8
6 0
3 years ago
Simplify the expresion <br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B3.%20%5Csqrt%5B4%5D%7B432%7D%20%7D%20" id="TexF
Bond [772]
\sqrt[4]{3. \sqrt[4]{432}}
= \sqrt[4]{3. \sqrt[4]{2^4.3^3} }
= \sqrt[4]{3.2.3^\frac{3}{4}}
= 3^\frac{1}{4}.2^\frac{1}{4}.3^\frac{3}{16}
= 3^\frac{7}{16}.2^\frac{1}{4}



6 0
3 years ago
I'm stuck. what do i do next??
Aneli [31]
Here is your solution,
(-5)^2 - √25 - 4 x (-14)/2
25 - √ 25 + 56/2
25 - √81/2
(25 - 9)/2 = 16/2 = 8

or
25 + √25 +56/2
25 + √81/2
(25 + 9)/2 = 34/2 = 17

So m = 8,17
6 0
3 years ago
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