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klasskru [66]
3 years ago
14

Latoya had a large collection of basketball cards. she gave half to her friend,Erin. And 1/4 to her brother. She now has 75 card

s. How many cards did she start with?
Mathematics
2 answers:
Kipish [7]3 years ago
5 0

For this case, the first thing we must do is define variables.

We have then:

x: initial amount of cards

We now write the equation that models the problem:

x - (\frac{1}{2}) x - (\frac{1}{4}) x = 75

(\frac{1}{4}) x = 75\\x = 75 * 4\\x = 300

Therefore, the initial amount of cards is 300

Answer:

Latoya had 300 cards at the beginning

malfutka [58]3 years ago
4 0
Layota gave away half of her cards and a quarter of her cards, totaling a loss of three-quarters (75%) of her cards. Thus, we know that her remaining cards (75) are 25% of her original total, and thus the total (x) divided by four. We can put this into an equation like the one below, and simply multiply both sides by four to get the original amount of cards Layota started with, 300. 

x/4 = 75 

x = 300


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Find the absolute minimum and absolute maximum values of f on the given interval. f(t) = t 25 − t2 , [−1, 5]
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Answer: Absolute minimum: f(-1) = -2\sqrt{6}

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Step-by-step explanation: To determine minimum and maximum values in a function, take the first derivative of it and then calculate the points this new function equals 0:

f(t) = t\sqrt{25-t^{2}}

f'(t) = 1.\sqrt{25-t^{2}}+\frac{t}{2}.(25-t^{2})^{-1/2}(-2t)

f'(t) = \sqrt{25-t^{2}} -\frac{t^{2}}{\sqrt{25-t^{2}} }

f'(t) = \frac{25-2t^{2}}{\sqrt{25-t^{2}} } = 0

For this function to be zero, only denominator must be zero:

25-2t^{2} = 0

t = ±\sqrt{2.5}

\sqrt{25-t^{2}} ≠ 0

t = ± 5

Now, evaluate critical points in the given interval.

t = -\sqrt{2.5} and t = - 5 don't exist in the given interval, so their f(x) don't count.

f(t) = t\sqrt{25-t^{2}}

f(-1) = -1\sqrt{25-(-1)^{2}}

f(-1) = -\sqrt{24}

f(-1) = -2\sqrt{6}

f(\sqrt{12.5}) = \sqrt{12.5} \sqrt{25-(\sqrt{12.5} )^{2}}

f(\sqrt{12.5}) = 12.5

f(5) = 5\sqrt{25-5^{2}}

f(5) = 0

Therefore, absolute maximum is f(\sqrt{12.5}) = 12.5 and absolute minimum is

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8 0
3 years ago
The statewide pass rates for ENGL&101 across Washington state community colleges is 68%. An instructor in the English depart
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Answer:

<em>The calculated value Z=1.2413 < 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is accepted </em>

<em>An instructor in the English department at CBC believes rates at CBC may be equal to the state average</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given Population proportion </em>

<em>                                     P=68%= 0.68</em>

<em>Sample proportion </em>

<em>                             </em>p^{-} =\frac{x}{n} = \frac{179}{250} = 0.716<em></em>

<em>Null hypothesis : H₀ : p = 0.68</em>

<em>Alternative Hypothesis :H₁ : p > 0.68</em>

<u><em>Step(ii)</em></u><em>:-</em>

<em>Test statistic</em>

<em>                          </em>Z = \frac{p^{-}-P }{\sqrt{\frac{P Q}{n} } }<em></em>

<em>                         </em>Z = \frac{0.716-0.68 }{\sqrt{\frac{0.68 X 0.32}{250} } }<em></em>

<em>                        Z = 1.2413</em>

<em>Level of significance </em>

<em>              </em>Z_{0.05} = 1.96<em></em>

<em>The calculated value Z=1.2413 < 1.96 at 0.05 level of significance</em>

<em>Null hypothesis is accepted </em>

<em>An instructor in the English department at CBC believes rates at CBC may be equal to the state average</em>

<em></em>

<em></em>

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3 years ago
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