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3 years ago

Help me and i’ll give brainliest. 8th grade math.

Mathematics

1 answer:

borishaifa [10]3 years ago

8 0

Answer:

y=2x+4

Step-by-step explanation:

get two points: (0,4) and (1,6)

do y2-y1 over x2-x1:

6-4 over 1-0

2 over 1 = 2

y-intercept is y coordinate of the x coordinate that is 0

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AD ??????? so confused what the

Andre45 [30]

Answer:

3.6 cm

Step-by-step explanation:

Triangle Proportionality Theorem

BD : DE = BA : AC

⇒ 6 : 10 = BA : 16

⇒ $\mathsf{\dfrac{6}{10} = \dfrac{BA}{16}}$

⇒ $\mathsf{BA=\dfrac{6}{10} \times16}$

⇒ BA = 9.6

AD = BA - BD

⇒ AD = 9.6 - 6 = 3.6 cm

4 0

2 years ago

Please help!! I dont know what to do!

Aliun [14]

The answer to this problem would be c.

7 0

3 years ago

an employee has an annual salary of $48,700. they receive $1,530 in health insurance and $2,810 in paid time off per year. they

Anna [14]

Compensation for the year:$51,810(deducting vehicle expense)

An employee makes 48,700+1,530(health insurance)+2,810(paid time)=

53,040. Also they receive 0.53 per mile x 9,000 miles=4,770

53,040 +4,770=57,810(employment compensation)

Personal work vehicle expense: 500 x 12 months=6,000

57,810 - 6,000= 51,810

6 0

3 years ago

Read 2 more answers

What is the length of the curve with parametric equations x = t - cos(t), y = 1 - sin(t) from t = 0 to t = π? (5 points)

zzz [600]

Answer:

B) 4√2

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Parametric Differentiation

Integration

Integrals
Definite Integrals
Integration Constant C

Arc Length Formula [Parametric]: $\displaystyle AL = \int\limits^b_a {\sqrt{[x'(t)]^2 + [y(t)]^2}} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle \left \{ {{x = t - cos(t)} \atop {y = 1 - sin(t)}} \right.$

Interval [0, π]

Step 2: Find Arc Length

[Parametrics] Differentiate [Basic Power Rule, Trig Differentiation]: $\displaystyle \left \{ {{x' = 1 + sin(t)} \atop {y' = -cos(t)}} \right.$
Substitute in variables [Arc Length Formula - Parametric]: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{[1 + sin(t)]^2 + [-cos(t)]^2}} \, dx$
[Integrand] Simplify: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx$
[Integral] Evaluate: $\displaystyle AL = \int\limits^{\pi}_0 {\sqrt{2[sin(x) + 1]} \, dx = 4\sqrt{2}$