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Hunter-Best [27]
4 years ago
8

Where does the graph of the function y=tan(x) have asymptotes?

Mathematics
2 answers:
Step2247 [10]4 years ago
7 0
At every pi/2 that doesn't result in a whole number value of pi. so 3pi/2, 5pi/2, etc..
Montano1993 [528]4 years ago
7 0

Answer:

y=\text{tan}(x) will have asymptote, when \text{cos}(x)=0.

Step-by-step explanation:

We are asked to find the asymptotes of the function y=\text{tan}(x).

We can represent tangent as \text{tan}(x)=\frac{\text{sin}(x)}{\text{cos}(x)}.

We know that a rational function is undefined, when denominator is zero. So our function will have asymptote, when \text{cos}(x)=0.

We know that \text{cos}(x)=0 at \pm \frac{\pi}{2}+n.

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Lisa [10]

Answer:

I think its C

Step-by-step explanation:

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3 years ago
Help with this pleaseeee​
ELEN [110]

Answer:

(- 3, 37) and (- \frac{5}{2}, \frac{63}{2} )

Step-by-step explanation:

Given the 2 equations

2x² - y + 19 = 0 → (1)

y + 11x = 4 → (2) ← subtract 11x from both sides

y = 4 - 11x → (3)

Substitute y = 4 - 11x into (1)

2x² - (4 - 11x) + 19 = 0

2x² - 4 + 11x + 19 = 0

2x² + 11x + 15 = 0 ← in standard form

(2x + 5)(x + 3) = 0 ← in factored form

Equate each factor to zero and solve for x

2x + 5 = 0 ⇒ 2x = - 5 ⇒ x = - \frac{5}{2}

x + 3 = 0 ⇒ x = - 3

Substitute these values into (3) for corresponding values of y

x = - \frac{5}{2} : y = 4 + \frac{55}{2} = \frac{63}{2} ⇒ (- \frac{5}{2}, \frac{63}{2} )

x = - 3 : y = 4 + 33 = 37 ⇒ (- 3, 37 )

4 0
3 years ago
Please help i will mark brainly
Vsevolod [243]
The answer to your question is positive
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Answer:

F

Step-by-step explanation:

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