Answer:
350 F to 100 F it take approx 87.33 min
Explanation:
given data
oven = 350◦F
cooling rack = 70◦F
time = 30 min
cake = 200◦F
solution
we apply here Newtons law of cooling
= -k(T-Ta)
=
(T(t) -Ta)
=
= -k(T-Ta)
-ky
= -ky
T(t) -Ta = (To -Ta)
T(t) = Ta+ (To -Ta)
put her value for time 30 min and T(t) = 200◦F and To =350◦F and Ta = 70◦F
so here
200 = 70 + ( 350 - 70 ) 
k = 0.025575
so here for T(t) = 100F
100 = 70 + ( 350 - 70 ) 
time = 87.33 min
so here 350 F to 100 F it take approx 87.33 min
Answer:
I believe the answer is esophagus
Answer:
Explanation:
N = 65
Area, A = 0.1 x 0.2 = 0.02 m^2
R = 10 ohm
ω = 29.5 rad/s
B = 1 T
(a) at t = 0
e = N x B x A x ω
e = 65 x 1 x 0.02 x 29.5
e = 38.35 V
(b) The maximum rate of change of magnetic flux is equal to the maximum value of induced emf.
Ф = 38.35 Wb/s
(c) e = NBAω Sinωt
e = 65 x 1 x 0.02 x 29.5 x Sin (29.5 x 0.05)
e = 38.174 V
(d) Maximum torque
τ = M B Sin 90
τ = N i A B
τ = N e A B / R
τ = 65 x 38.35 x 0.02 x 1 / 10
τ = 5 Nm
X=ut+0.5at²
1000 = 63.3u + 0.5 * 0.0323 * 63.3²
u = (1000 - 0.1615*63.3²)/63.3
u = 5.57 m/s
i don't even know if this is correct
Answer:
The answer is option D. Stored in the chemical bonds.
Hope it helps............