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Semmy [17]
3 years ago
5

An experiment on the earth's magnetic field is being carried out 1.00 m from an electric cable. What is the maximum allowable cu

rrent int eh cable if the experiment is to be accurate?
Physics
1 answer:
Whitepunk [10]3 years ago
4 0

Answer:

The allowed current in the cable is 1.15 A.

Explanation:

Given that,

Distance = 1.00 m

Suppose the magnetic field is 2.3\times10^{-5}\ T and  if the experiment is to be accurate to 1.0 %

We need to calculate the current

Using formula of magnetic field

B=\dfrac{\mu_{0}I}{2\pi r}

I=\dfrac{B\times2\pi r}{\mu_{0}}

Put the value into the formula

I=\dfrac{2.3\times10^{-5}\times2\times\pi\times1.00}{4\pi\times10^{-7}}

I=115\ A

If the experiment is to be accurate to 1.0%

Then,

We need to calculate the allowed current in the cable

I'=(1.0%)\times I

I'=\dfrac{1.0}{100}\times115

I'=1.15\ A

Hence, The allowed current in the cable is 1.15 A.

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A toy car accelerates at a constant rate from rest to a speed of 4 m/s in a time of 0.55 s. What was the magnitude of the accele
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On what factors does critical velocity depend on
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6 0
3 years ago
Can someone help me?!!!!!
german
<h2>Hello!</h2>

The answer is:

The first option,  the walker traveled 360m more than the actual distance between the start and the end points.

Why?

Since each block is 180 m long, we need to calculate the vertical and the horizontal distance, in order to calculate how farther did the travel walk between the start and the end points (displacement).

So, calculating we have:

Traveler:

Distance=NorthCoveredDistance+EastCoveredDistance

Distance=4*180m+3*180m=720m+540m=1260m

Actual distance between the start and the end point (displacement):

ActualDistance=\sqrt{NorthDistance+EastDistance}\\\\ActualDistance=\sqrt{NorthDistance^{2} +EastDistance^{2}}\\\\ActualDistance=\sqrt{(720m)^{2} +(540m)^{2}}\\\\ActualDistance=\sqrt{518400m^{2} +291600m^{2}}\\\\ActualDistance=\sqrt{810000m^{2}}=900m

Now, to calculate how much farter did the traveler walk, we need to use the following equation:

DistanceDifference=WalkerCoveredDistance-ActualDistance\\\\DistanceDifference=1260m-900m=360m

Therefore, we have that distance differnce between the distance covered by the walker and the actual distance is 360m.

Hence, we have that the walker traveled 360m more than the actual distance between the start point and the end point.

Have a nice day!

3 0
3 years ago
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