Therefore electric potential is V = 15000V.
What is electric potential?
The amount of labor required to convey a unit of electric charge from a reference point to a given place in an electric field is known as the electric potential (also known as the electric field potential, potential drop, or the electrostatic potential).
length of sparks d = 5 mm = 5 x 10^-2 m
(a) It is possible to find average values for the skin's surface and the electric field in dry air from outside sources. Electric field and spark length can be used to determine electric potential.
V = E.d
V = 15000V
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Less of a glass of water because a glass of water holds approximately 250 mil-liters of water
Answer:
Vy = 0
y(max) = 137,76 m
x(max) = 318 m
Explanation:
We are dealing with a projectile movement
And from problem statement we know:
θ = 60⁰ then sin θ = sin 60⁰ = √3/2 and cos 60⁰ = 1/2 and g = 9.8 m/sec²
V₀ = 60 m/sec
V₀x = V₀ *cosθ Vx = V₀x Vx = Constant then Vx = V₀ *cosθ
Then Vx = 60* 1/2 Vx = 30 m/sec
V₀y = V₀ *sinθ ⇒ V₀y =60*√3/2 ⇒ V₀y = = 30*√3 m/sec
Vy = V₀y * sin θ - g*t
When Vy = 0 (maximum height point) we are half of the way for the ball to hit the ground, then
Vy = 0 ⇒ V₀y - g*t = 0 ⇒ 30*√3 (m /sec) = 9,8 (m/sec²)* t
t = 30*√3/9.8 t = 5.30 sec
y(max) = y₀ + V₀y*t - 1/2 * g*t²
By substitution:
y (max) = 0 + 30*√3 * 5.30 - 0,5* 9.8* (5.3)²
y(max) = 275,40 - 137,64
y(max) = 137,76 m
And finally x(max)
x(max) = Vx *t = 30* 2*5,3
x(max) = 318 m
Answer:
Scientists have identified about a dozen major and several minor tectonic plates
Radius of curvature<span> of a spherical mirror = 2 × </span>Focal length<span>
and the ray of light is parallel to the principle axis if the incident </span><span>Passes through focus
therefore, focal length =30/2=<span>15cm
</span></span><span>The mirror should be placed at a distance of 15cm from the light bulb to produce this parallel light beam.</span>