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3 years ago

Which value of x makes the following equation true?

Mathematics

2 answers:

statuscvo [17]3 years ago

5 0

Answer:

the answer is c hope this helps

Step-by-step explanation:

-7-3=-10

-10x2=-20

-20+41=21

-3(-7)=21

fenix001 [56]3 years ago

3 0

Answer

in order to get the most correct answer you must plug the answer to get x

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What is the slope of the line that passes through the points ( 5 , 6 )and ( 5 , 9 ) ? Write your answer in simplest form.

Lapatulllka [165]

Answer:

Step-by-step explanation:

9-6

over

6-5

=3/1

simplify

m=3

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3 years ago

How do I solve this please? Can SOMEONE please help me this and the ones Iposted on my page.

vagabundo [1.1K]

Answer: $\dfrac{15}{64}$

Step-by-step explanation:

Given

Inside radius of figure $r_1=\frac{14}{2}=7\ ft$

Outside radius of figure $r_2=\frac{16}{2}=8\ ft$

Area of outside region is $A_1=\pi (8^2)$

Area of inside region $A_2=\pi (7)^2$

Area of shaded region $A_1-A_2$

Probability that point lies inside the shaded region is

$\Rightarrow P=\dfrac{A_1-A_2}{A_1}\\\\\Rightarrow P=\dfrac{\pi (8^2-7^2)}{\pi 8^2}\\\\\Rightarrow P=\dfrac{64-49}{64}\\\\\Rightarrow P=\dfrac{15}{64}$

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

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three postal workers can sort a stack of mail in 30 minutes, 30 minutes, and 60 minutes, respectively. find how long it takes th

OverLord2011 [107]

Answer:

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Step-by-step explanation:

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3 years ago

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21. In 4 + In(4x - 15) = In(5x + 19)

Alexxx [7]

Answer:

$x=-30;\quad \:I\ne \:0$

Step-by-step explanation:

$In\cdot \:4+In\left(4x-15\right)=In\left(5x+19\right)$

$\:4+In\left(4x-15\right):\quad -11nI+4nxI\\In\cdot \:4+In\left(4x-15\right)\\=4nI+nI\left(4x-15\right)\\\\\:In\left(4x-15\right):\quad 4nxI-15nI\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\a=In,\:b=4x,\:c=15\\=In\cdot \:4x-In\cdot \:15\\=4nxI-15nI\\=In\cdot \:4+4nxI-15nI\\\mathrm{Simplify}\:In\cdot \:4+4nxI-15nI:\quad -11nI+4nxI\\In\cdot \:4+4nxI-15nI\\\mathrm{Group\:like\:terms}\\=4nI-15nI+4nxI\\\mathrm{Add\:similar\:elements:}\:4nI-15nI=-11nI\\=-11nI+4nxI\\$

$\mathrm{Expand\:}In\left(5x+19\right):\quad 5nxI+19nI\\In\left(5x+19\right)\\=nI\left(5x+19\right)\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b+c\right)=ab+ac\\a=In,\:b=5x,\:c=19\\=In\cdot \:5x+In\cdot \:19\\=5nxI+19nI\\\\-11nI+4nxI=5nxI+19nI\\\\\mathrm{Add\:}11nI\mathrm{\:to\:both\:sides}\\-11nI+4nxI+11nI=5nxI+19nI+11nI\\Simplify\\4nxI=5nxI+30nI\\\mathrm{Subtract\:}5nxI\mathrm{\:from\:both\:sides}\\4nxI-5nxI=5nxI+30nI-5nxI\\\mathrm{Simplify}\\-nxI=30nI\\$

$\mathrm{Divide\:both\:sides\:by\:}-nI;\quad \:I\ne \:0\\\frac{-nxI}{-nI}=\frac{30nI}{-nI};\quad \:I\ne \:0\\\mathrm{Simplify}\\\frac{-nxI}{-nI}=\frac{30nI}{-nI}\\\mathrm{Simplify\:}\frac{-nxI}{-nI}:\quad x\\\frac{-nxI}{-nI}\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{-b}=\frac{a}{b}\\=\frac{nxI}{nI}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{xI}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=x\\\mathrm{Simplify\:}\frac{30nI}{-nI}:\quad -30\\\mathrm{Apply\:the\:fraction\:rule}:$

$\quad \frac{a}{-b}=-\frac{a}{b}\\\mathrm{Cancel\:the\:common\:factor:}\:n\\=\frac{30I}{I}\\\mathrm{Cancel\:the\:common\:factor:}\:I\\=-30\\x=-30;\quad \:I\ne \:0$

3 0

3 years ago