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creativ13 [48]
2 years ago
7

Find the value of x.

Mathematics
1 answer:
Harman [31]2 years ago
8 0
The answer to the question is 30
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Approximately how much money would Manny have if he invested $1,200 at an interest rate
quester [9]

Answer:

$1,701.64

Step-by-step explanation:

(see attached for reference)

recall that for compound interest, the following formula applies:

A = P [1 + (r/n) ] ^ (nt), where

A = final amount (we are asked to find this)

P = Principal amount = $1,200

r = interest rate = 5% = 0.05

t = 7 years

n = 12

Substituting these into the equation,

A = 1200 [1 + (0.05/12) ] ^ [(12)(7)]

A =  $1,701.64

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3 years ago
Tell whether this statement is sometimes, always, or never true. Identify the answer with a sketch. If B is a point between A an
Ksivusya [100]
The statement is always true
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3 years ago
5. Simplify<br> (7x2+ 8) - (x2 - 2)
Gennadij [26K]

Answer:

(7 \times 2 + 8) - ( {x}^{2}  - 2) \\ (14 + 8) - ( {x}^{2}  - 2) \\ 14 + 8 -  {x}^{2}  + 2 \\ 22 +  {x}^{2}  + 2 \\ 24 +  {x}^{2}

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

3 0
3 years ago
Divide. (18x^3 + 12x^2 - 3x) ÷ 6x^2
nlexa [21]

\bold{[ \ Answer \ ]}

\boxed{\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}}

\bold{[ \ Explanation \ ]}

  • \bold{Divide: \ \left(18x^3\:+\:12x^2\:-\:3x\right)\:\div \:6x^2}

\bold{-------------------}

  • \bold{Rewrite}

\bold{18x^3+12x^2-3x \ = \ x^2\frac{x\left(6x^2+4x-1\right)}{2}}

  • \bold{Rewrite}

\bold{x^2\frac{x\left(6x^2+4x-1\right)}{2}}

  • \bold{Multiply \ Fractions \ (a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c})}

\bold{\frac{x\left(6x^2+4x-1\right)x^2}{2}}

  • \bold{Rewrite}

\bold{x\left(6x^2+4x-1\right)x^2 \ = \ x^3\left(6x^2+4x-1\right)}

  • \bold{Simplify}

\bold{\frac{x^3\left(6x^2+4x-1\right)}{2}}

\boxed{\bold{[] \ Eclipsed \ []}}

3 0
3 years ago
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Step-by-step explanation:

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